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Blababa [14]
3 years ago
8

If you deposit Tsh 4000 into an account paying 9% annual interest compound monthly ,low long until there is Tsh 10000 in the acc

ount?
Mathematics
1 answer:
pav-90 [236]3 years ago
5 0

Answer:

It will take 10.63 years.

Step-by-step explanation:

Giving the following information:

Present value (PV)= $4,000

Future Value (FV)= $10,000

Interest rate (i)= 9% annual compounded

<u>To calculate the time required to reach $10,000, we need to use the following formula:</u>

n= ln(FV/PV) / ln(1+i)  

n= number of years

n= ln(10,000 / 4,000) / ln(1.09)

n= 10.63

It will take 10.63 years.

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3(4k+n) = 12k +n or 12k+3n?​
blagie [28]

Answer:

12k+3n

Step-by-step explanation:

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3 years ago
What is the expression of 3^9
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Well, 3^9 is the same thing as
3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3
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Newberg is 5 miles due north of the airport, and Rockport is 12 miles due east of the airport. How far apart are Newberg and Roc
amid [387]

Step-by-step explanation:

No of miles Newberg is north of airport = 5

No of miles Rockport is east of the airport = 12

No of miles Newberg and Rockport are apart = 12+5 =17

8 0
3 years ago
. A fence encloses a triangular field. There is
poizon [28]

Answer:

  • 16 posts

Step-by-step explanation:

<u>Sides are:</u>

  • 20 ft, 25 ft and 35 ft

<u>There are following number of posts on each of the sides:</u>

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<u>Total number:</u>

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6 0
3 years ago
Consider the following quadratic function Part 3 of 6: Find the x-intercepts. Express it in ordered pairs.Part 4 of 6: Find the
maksim [4K]

Answer:

The line of symmetry is x = -3

Explanation:

Given a quadratic function, we know that the graph is a parabola. The general form of a parabola is:

y=ax^2+bx+c

The line of symmetry coincides with the x-axis of the vertex. To find the x-coordinate of the vertex, we can use the formula:

x_v=-\frac{b}{2a}

In this problem, we have:

y=-x^2-6x-13

Then:

a = -1

b = -6

We write now:

x_v=-\frac{-6}{2(-1)}=-\frac{-6}{-2}=-\frac{6}{2}=-3

Part 3:

For this part, we need to find the x-intercepts. This is, when y = 0:

-x^2-6x-13=0

To solve this, we can use the quadratic formula:

x_{1,2}=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot(-1)\cdot(-13)}}{2(-1)}

And solve:

x_{1,2}=\frac{6\pm\sqrt{36-52}}{-2}x_{1,2}=\frac{-6\pm\sqrt{-16}}{2}

Since there is no solution to the square root of a negative number, the function does not have any x-intercept. The correct option is ZERO x-intercepts.

Part 4:

To find the y intercept, we need to find the value of y when x = 0:

y=-0^2-6\cdot0-13=-13

The y-intercept is at (0, -13)

Part 5:

Now we need to find two points in the parabola. Let-s evaluate the function when x = 1 and x = -1:

x=1\Rightarrow y=-1^2-6\cdot1-13=-1-6-13=-20x=-1\Rightarrow y=-(-1)^2-6\cdot(-1)-13=-1+6-13=-8

The two points are:

(1, -20)

(-1, -8)

Part 6:

Now, we can use 3 points to find the graph of the parabola.

We can locate (1, -20) and (-1, -8)

The third could be the vertex. We need to find the y-coordinate of the vertex. We know that the x-coordinate of the vertex is x = -3

Then, y-coordinate of the vertex is:

y=-(-3)^2-6(-3)-13=-9+18-13=-4

The third point we can use is (-3, -4)

Now we can locate them in the cartesian plane:

And that's enough to get the full graph:

8 0
1 year ago
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