Answer:
Step-by-step explanation:
We want an exponential function that goes through the two points (0, 8) and (2, 200).
Since a point is (0, 8), this means that y = 8 when x = 0. Therefore:
Simplify:
So we now have:
Likewise, the point (2, 200) tells us that y = 200 when x = 2. Therefore:
Solve for b. Dividing both sides by 8 yields:
Thus:
Hence, our exponential function is:
Answer:
How to solve your problem
−
7
2
−
2
2
+
3
−
2
+
5
3
−
2
-7y^{2}-2y^{2}+y^{3}y-2y+5y^{3}-2y
−7y2−2y2+y3y−2y+5y3−2y
Simplify
1
Combine exponents
−
7
2
−
2
2
+
3
−
2
+
5
3
−
2
-7y^{2}-2y^{2}+{\color{#c92786}{y^{3}y}}-2y+5y^{3}-2y
−7y2−2y2+y3y−2y+5y3−2y
−
7
2
−
2
2
+
4
−
2
+
5
3
−
2
-7y^{2}-2y^{2}+{\color{#c92786}{y^{4}}}-2y+5y^{3}-2y
−7y2−2y2+y4−2y+5y3−2y
2
Combine like terms
−
7
2
−
2
2
+
4
−
2
+
5
3
−
2
{\color{#c92786}{-7y^{2}}}{\color{#c92786}{-2y^{2}}}+y^{4}-2y+5y^{3}-2y
−7y2−2y2+y4−2y+5y3−2y
−
9
2
+
4
−
2
+
5
3
−
2
{\color{#c92786}{-9y^{2}}}+y^{4}-2y+5y^{3}-2y
−9y2+y4−2y+5y3−2y
3
Combine like terms
−
9
2
+
4
−
2
+
5
3
−
2
-9y^{2}+y^{4}{\color{#c92786}{-2y}}+5y^{3}{\color{#c92786}{-2y}}
−9y2+y4−2y+5y3−2y
−
9
2
+
4
−
4
+
5
3
-9y^{2}+y^{4}{\color{#c92786}{-4y}}+5y^{3}
−9y2+y4−4y+5y3
4
Rearrange terms
−
9
2
+
4
−
4
+
5
3
{\color{#c92786}{-9y^{2}+y^{4}-4y+5y^{3}}}
−9y2+y4−4y+5y3
4
+
5
3
−
9
2
−
4
{\color{#c92786}{y^{4}+5y^{3}-9y^{2}-4y}}
y4+5y3−9y2−4y
Solution
4
+
5
3
−
9
2
−
4
the perimeter is simply the sum of all its sides.
(6a+8)+(12a)+(6a+8)+(10a-4)
34a + 16 - 4
34a + 12.
<span>b^4 − b^3 + b − 1
=(</span><span>b^4 − b^3) + (b − 1)
= b^3(b - 1) + (b - 1)
=(b - 1)(b^3 + 1)</span>
Step-by-step explanation:
if you are given an equation of a form y=kx+b, k is gradient and b is y-intercept
in c you can write this equation as y=(2x/3)-2,so gradient = 2/3 and y-intercept =-2
in e:6y=2x+3
y=x/3+1/2,gradient = 1/3, y-intercept=1/2
