Answer=10 10gram weights
10*10grams=100grams
therefore the weight would be even on both sides
Answer:
4th option - over the interval (4,7) the local minimum is -7
Step-by-step explanation:
There's only one local minimum in this graph and it's the one between (4,7), so this is the only plausible answer.
<span><span>y = 2 + 2sec(2x)
The upper part of the range will be when the secant has the smallest
positive value up to infinity.
The smallest positive value of the secant is 1
So the minimum of the upper part of the range of
y = 2 + 2sec(2x) is 2 + 2(1) = 2 + 2 = 4
So the upper part of the range is [4, )
The lower part of the range will be from negative infinity
up to when the secant has the largest negative value.
The largest negative value of the secant is -1
So the maximum of the lower part of the range of
y = 2 + 2sec(2x) is 2 + 2(-1) = 2 - 2 = 0
So the lower part of the range is (, 0].
Therefore the range is (, 0] U [4, )
</span>
</span>
Answer:
f^-1(x) = x - 2
Step-by-step explanation:
To find the inverse of a function in terms of x and y, you would sway x and y in the function. We can rewrite f(x) = x + 2 as y = x + 2, since f(x) is basically y in a function. The inverse of y = x + 2 would be x = y + 2. Now, solve for y.
x = y + 2
-2 both sides.
x - 2 = y
y = x - 2
The inverse of y = x + 2 would be y = x - 2, so the inverse of f(x) = x + 2 would be f^-1(x) = x - 2 (f^-1(x) means the inverse of f(x)).
f^-1(x) = x - 2
I hope you find this helpful. :)
