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Mrac [35]
3 years ago
6

Plz help!! 20 points!! on the line plz give me a real answer

Mathematics
1 answer:
erastova [34]3 years ago
3 0

Answer:

62.5 feet

Step-by-step explanation:

first you find the area of the triangles by using the formula b*h /2 to get 9 3/8.  then since they are all the same size you can multiply it by 4 to get 37.5.  then you find the area of the square which is 25.  finally add the totals together to get 62.5

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Solve for x given BD = 4x+3 and AE = 4x+8. Assume B is the midpoint of segment AC and D is the midpoint of segment CE.
wolverine [178]

Answer: The fraction x = 1/2 or its equivalent decimal form x = 0.5

================================================

Work Shown:

AE = 2*(BD)

4x+8 = 2*(4x+3)

4x+8 = 8x+6

8-6 = 8x-4x

2 = 4x

4x = 2

x = 2/4

x = 1/2

x = 0.5

note: the first equation is set up basically saying that AE is twice that of BD; put another way, BD is half as long as AE. This is one property of midsegments. Another property is that AE and BD are parallel.

another note: if x = 0.5, then AE = 4*x+8 = 4*0.5+8 = 10 while BD = 4*x+3 = 4*0.5+3 = 5, showing that AE is indeed two times longer than BD.

8 0
3 years ago
What is twice the sum of 3 and 1<br> 1. Multiply by 2<br> 2. Divide by 2<br> 3. Add 2
faltersainse [42]

Answer:

10

Step-by-step explanation:

Twice the sum of 3 and 1 is 8.

8 times two is 16.

16 divided by 2 is 8.

8 plus 2 is 10.

6 0
3 years ago
Read 2 more answers
Use the given information to find the measures of all angles formed by parallel lines a and b, and transversal m. b One angle is
Anna35 [415]

Answer:∠1 = ∠3 = ∠5 = ∠7 = 77.5°

∠2 = ∠4 = ∠6 = ∠8 = 102.5°

Step-by-step explanation:

In the picture attached, the parallel lines and the transversal are shown.

8 angles are formed, where:

∠1 ≅ ∠3 ≅ ∠5 ≅ ∠7

∠2 ≅ ∠4 ≅ ∠6 ≅ ∠8

On the other hand, ∠1 + ∠2 = 180°, and ∠2 is 25° greater than ∠1, that is ∠1 + 25° = ∠2, therefore:

∠1 + ∠1 + 25° = 180°

2∠1 = 180° - 25°

∠1 = 155°/2

∠1 = 77.5°

and

∠2 = 77.5° + 25° = 102.5°

4 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=4y%20%2B%208%20%3D%202" id="TexFormula1" title="4y + 8 = 2" alt="4y + 8 = 2" align="absmiddle"
soldi70 [24.7K]

4y+8=2\qquad|\text{subtract 8 from both sides}\\\\4y=-6\qquad|\text{divide both sides by 4}\\\\y=-\dfrac{6}{4}\\\\\boxed{y=-\dfrac{3}{2}\to y=-1.5}

8 0
4 years ago
Read 2 more answers
Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one sam
lisov135 [29]
This is a system
x is the number of advanced tickets sold
y is the number of same day tickets sold
once you label your variables then write the equations
x+ y = 45 total tickets sold
20x + 25y = 1050 money taken in
multiply the top equation by -20 and the x will drop out
-20x - 20y = -900
20x + 25y = 1050. Add the equations result is
5y = 150, divide by 5 ,
y or same day tickets cost $30
substitute 30 into first equation
x + 30 = 45 therefore x = 15
4 0
3 years ago
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