Answer:
110°
Step-by-step explanation:
mFG = 2×<FEG = 2×55 = 110°
Answered by GAUTHMATH
Answer: 48 sold-out performances must be played in order for you to break even.
Step-by-step explanation:
Let x represent the number of sold-out performances must be played in order for you to break even.
You invest in a new play. The cost includes an overhead of $30,000, plus production costs of $2500 per performance. This means that the total cost of x sold out performances would be
2500x + 30000
A sold-out performance brings you $3125. This means that he total revenue from x sold out performances would be
3125x
To break even, cost = revenue
Therefore,
2500x + 30000 = 3125x
3125x - 2500x = 30000
625x = 30000
x = 30000/625
x = 48
Answer:
The volume of a prism on its own = 248.5cm^3
The volume of a cylinder = 87.92cm^3
Step-by-step explanation:
The volume does not change for the prism as the hole was drilled.
We can show the drilled space with v(l) and (p) for prism V
v(l) 248.5p - 87.92p + 87.92p
= 248.5p
Answer:
a. Genre with highest mean is drama. Mean is 72.10
B. 10.46 is difference between means of comedy and horror
C. Horror has the lowest minimum value at 25.00
Action and comedy both have the highest maximum value at 93.00
Step-by-step explanation:
First create a table with the data provided like I did in the attachment. It would give a clearer picture of what your answers should be.
1. Which genre has the highest mean score?
From the table, we have the means as:
Action = 58.63
Comedy = 59.11
Drama = 72.10
Horror = 48.65
The genre with the highest score is drama at 72.10
2. Difference in mean score between comedy and horror
Mean of comedy = lc = 59.11
Mean of horror = ly = 48.65
Difference = lc-ly
= 59.11 - 48.65
= 10.46
3. The genre with lowest score is the genre with the lowest minimum value. This genre is horror and the lowest minimum is 25.00
The genre with highest minimum value is that whose maximum value is the highest out of all the genres. Both action and comedy have the highest maximum value at 93.00
For the first 60 positive integers, a = 1, n = 60, l = 60.
Sn = n/2(a + l)
s = 60/2(1 + 60) = 30(61)
For the next 60 positive integer, a = 61, n = 60, l = 120
Sum = 60/2(61 + 120) = 30(61 + 120) = 30(61) + 30(120) = s + 3600
Sum of first 120 positive integers = s + s + 3600 = 2s + 3600
