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Kisachek [45]
4 years ago
15

If a is the average (arithmetic mean) of 4x and 7, b is the average of 5x and 6, and c is the average of 3x and 11, what is the

average of a, b, and c, in terms of x?
Mathematics
1 answer:
Debora [2.8K]4 years ago
7 0

Answer:

2x+4

Step-by-step explanation:

Given that a is the average (arithmetic mean) of 4x and 7, b is the average of 5x and 6, and c is the average of 3x and 11

By definition of arithmetic mean,

we have a=\frac{4x+7}{2} \\b=\frac{5x+6}{2} \\c=\frac{3x+11}{2}

Let us calculate sum of a,b,c in terms of x

a+b+c = \frac{4x+7+5x+6+3x+11}{2} \\=6x+12

Average = sum/3 = \frac{6x+12}{3} =2x+4

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3 years ago
A city hosted a music festival that included three concerts. According to the sales database, 28% of the audience attended the f
Vitek1552 [10]

Answer:

P(X\cap Y\cap Z)=0.05

Step-by-step explanation:

From the question we are told that:

Percentage of audience in first concert P(X)=0.28

Percentage of audience in second concert P(Y)=0.42

Percentage of audience in third concert P(Z)=0.30

Audience Percentage at at-least one concert P(X \cup Y \cup Z)=0.80

Percentage of audience at first & second concert P(X \cap Y)=0.10

Percentage of audience in first & third concert P(X \cap Z)=0.08

Percentage of audience in second & third concert P(Y\cap Z)=0.07

 

Generally the equation for probability of attending all concerts P(X\cap Y\cap Z)is mathematically given by

P(X \cup Y \cup Z)=P(X)+P(Y)+P(Z)-P(X \cap Y)-P(X \cap Z)-P(Y\cap Z)+P(X\cap Y\cap Z)

P(X\cap Y\cap Z)=P(X \cup Y \cup Z)-P(X)-P(Y)-P(Z)+P(X \cap Y)+P(X \cap Z)+P(Y\cap Z)

P(X\cap Y\cap Z)=0.80-0.28-0.42-0.30+0.10+0.80+0.70

P(X\cap Y\cap Z)=0.05

Therefore the probability that a randomly selected audient attended all the concerts

P(X\cap Y\cap Z)=0.05

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3 years ago
Helppp...!!! please...!!!​
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Answer:

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.000025 in scientific notation
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Answer:

2.5 \times 10^{-5}

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