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RUDIKE [14]
2 years ago
9

Help me please!!!!!!

Mathematics
1 answer:
Rashid [163]2 years ago
5 0
A, C, D, E . all of them are true.
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If m< BOE = 130 degrees and m< cob = 80 degrees
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6 0
3 years ago
Someone help ASAP!!!!!!
Alchen [17]

Answer:

Length, l = 11 ft.

Width, w = 9 ft.

Step-by-step explanation:

From the given data, the area of the rectangle = 99 ft².

Area of the rectangle = Length, l X Width, w

Here, Length, l = 7 more than twice the width

⇒       Length, l = 7 + 2w

Therefore, Area, A = 99 = (7 + 2w)w

⇒ 99 = 7w + 2w²

⇒ 2w² + 7w - 99 = 0

Solve the Quadratic equation using the formula: x = $ \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} $ for the quadratic equation ax² + bx + c = 0.

Therefore, w = $ \frac{-7 \pm \sqrt{7^2 -4(2)(-99)}}{2(2)} $

$ = \frac{-7 \pm \sqrt{49 + 8(99)}}{4} $

$ = \frac{-7 \pm + \sqrt{841}}{4} $

Since, $ \sqrt{841} = 29 $ we get:

$ w = \frac{-7 \pm 29}{4} $

This gives two values of 'w', viz., w = $ \frac{-7 - 29}{4} $, $ \frac{-7 + 29}{4} $

$ \implies w = \frac{22}{4}, \frac{-36}{4} $

⇒ w = $ \frac{22}{4} $, -9.

We take the integer values.

If w = -9, then l = 2(-9) + 7

⇒ l = - 18 + 7 = - 11

Therefore, the length, l of the rectangle = - 11 ft.

and the width, w of the rectangle = - 9 ft.

Hence, the answer.

3 0
3 years ago
In another problem in my homework, it says look at problem 4, problem 4 has to do with the question about seans team when it had
notka56 [123]
I dont know because I’m confused
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3 years ago
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