Answer:
Step-by-step explanation:
a) so initially there will be a total of 14 marbles in the bag since none have been removed yet. This means the probability of picking one red marble will be 6/14 or simplified, 3/7. However, the next time you pick a marble there will only be 13 marbles in the bag and only 5 red marbles, giving you a probability of 5/13. To get the next red marble, there will only be 12 marbles left in the bag with only 4 red marbles remaining. The probability of this is 4/12 or simplified, 1/3. In order to find the probability of picking 3 total red marbles, you need to multiply those probabilities together, so: (3/7)(5/13)(1/3) for an answer of 5/91 or a 0.0549% chance
b) I am not sure I fully understand how this question is possible if there is only one green marble and the marbles are not being replaced. My best guess would be a 0% chance since you cannot get 2 green marbles without replacement.
c) Again there are 14 marbles in the bag, that means the probability of picking a blue marble is 3/14, then, to find the probability of getting a yellow marble, you get 4/13, remember there is one less marble in the bag because you already took out a blue marble. Then simply multiply those probabilities together: (3/14)(4/13) for 6/91 probability or 0.0659% chance.
d) I am not entirely sure. If you want the probability of the red first then blue it is 9/91, and if it is blue then red, it is also 9/91.
