hours each day.
Step-by-step explanation:
The given function models the number of cars that are put through a quality control test each hour at a car production factory.
The given function is
We need to find the number of hours does the quality control facility operate each day.
Rewrite the given function it factored form.
Taking out the common factors from each parenthesis.
The factored form of given function is c(t)=-(t-10)(t+2).
Equate the function equal to 0 to find the x-intercept.
Number of hours cannot be negative. So from t=0 to t=10 quality control facility operate the cars.
Therefore the quality control facility operates for 10 hours each day.
Answer:
Step-by-step explanation:
I have a app called photomath, I really hope this works.
Answer:
Answer Below
Step-by-step explanation:
a. 2L+2W≥40
thats equal to 12+2W≥40 since it says the length is 6
That means 2W≥28
That means width ≥ 14
so the width can be 14 or greater
b. Smallest possible width is 14 because the inequality
For the answer to the question above,
The mean value theorem states the if f is a continuous function on an interval [a,b], then there is a c in [a,b] such that:
<span>f ' (c) = [f(b) - f(a)] / (b - a) </span>
<span>
So [f(a) - f(b)] ( b - a ) = [sin(3pi/4) - sin(pi/4)]/pi </span>
= [sqrt(2)/2 - sqrt(2)/2]/pi = 0
So for some c in [pi/2, 3pi/2] we must have f ' (c) = 0
In general f ' (x) = (1/2) cos (x/2)
We ask ourselves for what values x in [pi/2, 3pi/2] does the above equation equal 0.
0 = (1/2) cos (x/2)
0 = cos (x/2)
x/2 = ..., -5pi/2, -3pi/2, -pi/2, pi/2, 3pi/2, 5pi/2,...
x = ..., -5pi, -3pi, -pi, pi. 3pi, 5pi, ....
and x = pi is the only solution in our interval.
So c = pi is a solution that satisfies the conclusion of the MVT
