0.55 quick maths boiiiiiiuu
Answer:
The probability of observing between 43 and 64 successes=0.93132
Step-by-step explanation:
We are given that
n=100
p=0.50
We have to find the probability of observing between 43 and 64 successes.
Let X be the random variable which represent the success of population.
It follows binomial distribution .
Therefore,
Mean,
Standard deviation , 
![\sigma=\sqrt{100\times 0.50(1-0.50)]](https://tex.z-dn.net/?f=%5Csigma%3D%5Csqrt%7B100%5Ctimes%200.50%281-0.50%29%5D)

Now,






Hence, the probability of observing between 43 and 64 successes=0.93132
5 x 13
65 x 1
This isn't the only factorization, there's also the 65 and 1.
Answer:
As long as the sample size n is large enough: The average IQ of Americans in the sample will be normally distributed.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean
and standard deviation
, the sample means with size n of at least 30 can be approximated to a normal distribution with mean
and standard deviation 
So the correct answer is:
As long as the sample size n is large enough: The average IQ of Americans in the sample will be normally distributed.
Answer: $800 because if you have a light that is $2,000 and it loses %10 of its price per month, and June is 4 months away, then it is only $800.
4 x .1 = .4 so $2,000 x .4 = $800