Answer:
C. (3x2 - 10) (x - 2)
Step-by-step explanation:
3x^2 - 16x +20
Step 1: Sum = - 16x
Product = 60x^2
Step 2: Find 2 numbers that their sum is -16 and their product is 60. If you do that correctly, then you will get two numbers: 10 and -6
Step 3: Replace -16x with the two numbers found in step 2, then you will have; 3x^2 - 6x - 10x + 20
Step 4: Factorise the equation in step 3, like so;
(3x^2 - 6x)(- 10x + 20)
3x(x - 2) -10(x - 2)
(3x - 10)(x - 2)
To check if the answer is correct, expand the bracket: (3x - 10)(x - 2)
If the bracket is opened properly, you will get 3x^2 - 16x + 20
Answer:
D
Step-by-step explanation:
p^2
Answer:
(2,4)
Step-by-step explanation:
We have the system:
y=x+2
y=3x-2.
This is already setup for substitution.
I'm going to replace my first y with what the second y equals.
That is, I'm going to write 3x-2=x+2.
Time to solve the following for x:
3x-2=x+2
Subtract x on both sides:
2x-2= 2
Add 2 on both sides:
2x. = 4
Divide both sides by 2:
x. = 2
Now that we know x=2 and we have an equation that relates x to y: either y=x+2 or y=3x-2, doesn't matter which we use, we can find y.
So we y=x+2 with x=2 which means y=2+2=4.
So the solution, the intersection, is (2,4).
I think this is a least common multiple question
So they would all arrive on day 504, (which probably is a few years)
8 = 2 × 2 × 2
18 = 2 × 3 × 3
21 = 3 × 7
I might be right I might be wrong, IM not positively sure but yknow
Answer:
B
Step-by-step explanation:
