There are only 5 blue cards, 2 green cards and 4 red cards in a pack.

Ugo [173]

Answer:

Step-by-step explanation:

Summation means that you are adding together all the numbers that result from putting in the numbers 5-11 for i:

(-7 - 6(5)) + (-7 - 6(6)) + (-7 - 6(7)) + ( -7 - 6(8)) + ( -7 - 6(9)) + ( -7 - 6(10)) + ( -7 - 6(11)) which gives you the numbers:

-37 + -43 + -49 + -55 + -61 + -67 + -73 = -385

4 0

4 years ago

In the 1980s land prices in Japan surged upward in a ""speculative bubble."" Land prices then fell for 11 straight years between

Aloiza [94]

Answer:

Step-by-step explanation:

Given the supply of land is perfectly inelastic, the drop in prices must have resulted from decreased demand for land. The demand for land would fall if there were less of a return on the land (i.e., rent), so we can safely assume that land rent fell in Japan between 1990 and 2001. The shifts from D3 to D2 to D1 demonstrate graphically what happened in Japan.

7 0

3 years ago

Select all situations that can be modeled with a linear function. A taxi charges an initial fee of $2.00 and $1.50 for each addi

stiks02 [169]

The taxi, the airplane, and the pizza can be shown as linear functions

3 0

3 years ago

Solve the quadratic equation x2 – 14x + 40 = 0

goldfiish [28.3K]

What 2 numbers multiply to get 40 and add to get -14
-10 and -4

(x-4)(x-10)=0
set to zero

x-4=0
x=4

x-10=0
x=10

x=4 and 10

3 0

3 years ago

PLEASE HELP QWQ AsAp with these 4 questions

den301095 [7]

Answer:

Step-by-step explanation:

I can't believe I'm doing this for 5 points, but ok!

For the first 3, we are going to multiply to find the value of that 3 x 3 matrix by picking up the first 2 columns and plopping them down at the end and then multiplying through using the rules for multiplying matrices:

$\left[\begin{array}{ccccc}7&4&6&7&4\\-4&8&9&-4&8\\1&8&7&1&8\end{array}\right]$ and from there find the sum of the products of the main axes minus the sum of the products of the minor axes, as follows (I'm not going to state the process in the next 2 problems, so make sure you follow it here. This is called the determinate. The determinate is what you get when you evaluate or find the value of a matrix. Just so you know):

$(7*8*7)+(4*9*1)+(6*-4*8)-[(1*8*6)+(8*9*7)+(7*-4*4)]$ which gives us:

392 + 36 - 192 - [48 + 504 - 112] which simplifies to

236 - 440 which is -204

On to the second one:

$\left[\begin{array}{ccccc}-8&-4&-1&-8&-4\\1&7&-3&1&7\\8&9&9&8&9\end{array}\right]$ and multiplying gives us

$(-8*7*9)+(-4*-3*8)+(-1*1*9)-[(8*7*-1)+(9*-3*-8)+(9*1*-4)]$ which gives us:

-504 + 96 - 9 - [-56 + 216 - 36] which simplifies to

-417 - 124 which is -541, choice c.

Now for the third one:

$\left[\begin{array}{ccccc}-2&-2&-5&-2&-2\\2&7&-3&2&7\\8&9&9&8&9\end{array}\right]$ and multiplying gives us

$(-2*7*9)+(-2*-3*8)+(-5*2*9)-[(8*7*-5)+(9*-3*-2)+(9*2*-2)]$ which gives us:

$-126+48-90-[-280+54-36]$ which simplifies to

-168 - (-262) which is 94, choice c again.

Now for the last one. I'll show you the set up for the matrix equation; I solved it using the inverse matrix. So I'll also show you the inverse and how I found it.

$\left[\begin{array}{cc}-4&-5&\\-6&-8\\\end{array}\right]$ $\left[\begin{array}{c}x\\y\\\end{array}\right]$ = $\left[\begin{array}{c}-5\\-2\\\end{array}\right]$ and I found the inverse of the 2 x 2 matrix on the left.

Find the inverse by:

* finding the determinate

* putting the determinate under a 1

* multiply that by the "mixed up matrix (you'll see...)

First things first, the determinate:

|A| = (-4*-8) - (-6*-5) which simplifies to

|A| = 32 - 30 so

|A| = 2; now put that under a 1 and multiply it by the mixed up matrix. The mixed up matrix is shown in the next step:

$\frac{1}{2}\left[\begin{array}{cc}-8&5\\6&-4\end{array}\right]$ (to get the mixed up matrix, swap the positions of the numbers on the main axis and then change the signs of the numbers on the minor axis). Now we multiply in the 1/2 to get the inverse:

$\left[\begin{array}{cc}-4&\frac{5}{2}\\3&-2\\\end{array}\right]$ Multiply that inverse by both sides of the equation. This inverse "undoes" the matrix that's already there (like dividing the matrix that's already there by itself) which leaves us with just the matrix of x and y. Multiply the inverse matrix by the solution matrix:

$\left[\begin{array}{c}x&y\end{array}\right] =\left[\begin{array}{cc}-4&\frac{5}{2} \\3&-2\end{array}\right] *\left[\begin{array}{c}-5&-2\\\end{array}\right]$ and that right side multiplies out to

x = 20 - 5 which is

x = 15 and

y = -15 + 4 which is

y = -11

(It works, I checked it)

7 0

3 years ago