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Maru [420]
2 years ago
8

lengths of two sides of a triangle are 6cm and 10cm. the two whole numbers between which the length of third side lie is​

Mathematics
1 answer:
solong [7]2 years ago
7 0

Answer:

plz mark me as brainiest

Step-by-step explanation:

10-6=4

10+6 =16

4 >x>16.

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-3x - 8 + 6x = 7 wat is the answer
Aliun [14]
3x-8+6x=7
9x-8=7
9x=15
x=9/15
x=3/5

7 0
3 years ago
Read 2 more answers
PLEASE HELPPPPP
natulia [17]
Take Saturdays total of $620 and subtract Fridays total of $460 to get $160. Divide that by the difference of the number of pies sold on Friday and Saturday to get $8. Take the $8 and multiply by number of pies sold on Friday (20) to get $160. Take that number and subtract it from the total sold on Friday ($460) to get $300. Divide that by how many cakes were sold on Friday (30) and get $10.
So therefore:

Pies - $8 each
Cakes - $10 each
6 0
3 years ago
Help me please ASAP!!
Tcecarenko [31]
Hello there k12 user. - i am in k12 too :)

cough.


use mathpapa look it up it should give your anwser i cant copy and paste it, but its there
just put in the numbers
6 0
3 years ago
The price of an item selling at 150% of its $63 value is
Triss [41]
You just have to multiply the percentage by the amount:
(150/100)×$63 
1.5×$63= $94.50
If you aren't allowed a calculator, then just find half of $63 (the 0.5 of the fraction) and add it to $63 (the 1. of the fraction).
$63÷2= $31.5
$63+$31.5= $94.50
8 0
3 years ago
Read 2 more answers
A manufacturer has been selling 1000 flat-screen TVs a week at $500 each. A market survey indicates that for A manufacturer has
luda_lava [24]

Answer:

a) Demand function: q=6000-10\cdot p

b) The rebate should be of $200, so the sale price becomes $300 per unit.

c) The rebate should be of $150, so the sale price becomes $350 per unit.

Step-by-step explanation:

a) In this case, we have a known point of the demand function (1000 units sold at $500), and the slope of a linear function (increase by 100 units fora decrease in $10).

We can express the demand function (linear) as:

q=b+m\cdot p

To calculate the slope m, we use:

m=\Delta q/\Delta p=(+100)/(-10)=-10

To calculate b, we use the known point and the calculated slope:

q=b+m\cdot p\\\\b=q-m\cdot p=1000-(-10)\cdot (500)=1000+5000=6000

Then the demand function is:

q=6000-10\cdot p

b) The revenue can be expressed as:

R=q\cdot p = (6000-10p)\cdot p=6000p-10p^2

To maximize, we can derive and equal to zero

dR/dp=6000-2*10p=0\\\\20p=6000\\\\p=300

The rebate should be of $200, so the sale price becomes $300 per unit.

c) If we take into account the cost, we have that

R=q\cdot p-C=(6000p-10p^2)-(68000+100q)\\\\R=(6000p-10p^2)-(68000+100(6000-10p))\\\\R=6000p-10p^2-(68000+600000-1000p)\\\\R=-10p^2+7000p-668000

To maximize, we can derive and equal to zero

dR/dp=-20p+7000=0\\\\p=7000/20=350

The rebate should be of $150, so the sale price becomes $350 per unit.

5 0
3 years ago
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