Answer:
![\large\boxed{4\sqrt[3]{64}=16}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B4%5Csqrt%5B3%5D%7B64%7D%3D16%7D)
Step-by-step explanation:
![\sqrt[3]{a}=b\iff b^3=a\\\\4\sqrt[3]{64}=(4)(4)=16\\\\\sqrt[3]{64}=4\ \text{because}\ 4^3=64](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Ba%7D%3Db%5Ciff%20b%5E3%3Da%5C%5C%5C%5C4%5Csqrt%5B3%5D%7B64%7D%3D%284%29%284%29%3D16%5C%5C%5C%5C%5Csqrt%5B3%5D%7B64%7D%3D4%5C%20%5Ctext%7Bbecause%7D%5C%204%5E3%3D64)
Answer:
(5.5, 6)
Step-by-step explanation:
Find the difference between them and then divide by 2 and add to one point
I think it’s 16
Radius of circle = 32
Diagonal of circle = 64 cm
So 64 divided by 8 = 16
Mark me as brainliest
12q+3r=15
-4q-4r=-44
-4q=-44+4r
q=11-r
12(11-r)+3r=15
132-12r+3r=15
132-9r=15
117=9r
r=13
-4q-4(13)=-44
-4q-52=-44
-4q=8
q=-2
