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Sauron [17]
3 years ago
9

A camera company packs each camera in a cube­shaped box with side lengths of 1/2 ft. Then the company ships the cameras in a con

tainer with dimensions of 5 1/2 ft by 7 1/2 ft by 4 1/2 ft. What is the maximum number of camera boxes that will fit in the container?
Mathematics
1 answer:
I am Lyosha [343]3 years ago
7 0

Answer:

1,485 camera boxes

Step-by-step explanation:

1/2 ft is 6 inches. So, the cube-shaped camera box has side lengths of 6 inches. Meaning, the volume of the camera box is (6 * 6 * 6) inches^3, or 216 inches^3. Same principle for finding the volume of the container. 5 1/2 ft = 66 inches, 7 1/2 ft = 90 inches, and 4 1/2 ft = 54 inches. So, the volume of the container is (66 * 90 * 54) inches^3, or 320,760 inches^3. Since we are trying to find out how many camera boxes can fit in the container, we divide the volume of the container by the volume of one camera box. The problem looks like this: 320,760 / 216. The quotient, 1,485, is how many camera boxes that can fit inside the container, and is thus our final answer.

brainliest? please. I'll even say a joke if i have to

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3 years ago
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4 years ago
What is the x-intercept of the line described by the equation?
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(0,-6)

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