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tigry1 [53]
3 years ago
11

Please help solve please

Mathematics
1 answer:
Jet001 [13]3 years ago
6 0

Answer: number of guest 12 20 number of tables 6 13

Step-by-step explanation:

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Evaluate The Exsperession. Show your work<br><br><br>6.7-3^2.9+4^3<br>or
Rom4ik [11]
  • <em>Answer:</em>

<em>25</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there !</em>

<em>6×7 - 3²×9 + 4³ =</em>

<em>   1. raise the numbers to power</em>

<em>= 6×7 - 9×9 + 64</em>

<em>   2. we perform the multiplications</em>

<em>= 42 - 81 + 64</em>

<em>   3.  we perform addition and subtraction</em>

<em>= (42 + 64) - 81</em>

<em>= 106 - 81</em>

<em>= 25</em>

<em>Good luck !</em>

7 0
3 years ago
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2)) There are 32 1/5 calories in<br> a candy bar. How many calories<br> are there in 33 candy bars?
CaHeK987 [17]
If 1 candy bar is 32 1/5 then you would multiply 32 1/5 x 33 =1062.6
≈ 1063 calories
6 0
3 years ago
Javier drove 45 miles. This represent 60% of his entire trip. What is the total number of miles in Javier’s trip
Andrews [41]
60% of trip = 45 miles

let total trip distance = l

60% is given by multiplying by 0.6

So;

0.6l = 45 \\ \\ l = \frac{45}{0.6} \\ \\ \boxed{l = 75}

Your answer is 75 miles
8 0
3 years ago
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The triangle below is isosceles. Find the length of side x in simplest radical form with
BigorU [14]
That all cause u the length of the time

6 0
2 years ago
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A cat had a litter of 5 kittens. If each sex is equally likely, what is the probability that 3 or less were female kittens?
ASHA 777 [7]

Answer:

0.8125

Step-by-step explanation:

In this question, we are tasked with calculating the probability that 3 or less of her kittens were female.

Since each bsex is of likely probability, the probability of a male kitten = probability of a female kitten = 0.5

Now to calculate for 3 or less female kitten we are calcualting P(f) ≤ 3

In each case, we use the Bernoulli approximation

P(f) ≤ 3 = 5C3 m^{2} f^{3} + 5C2 m^{2}  f^{3} + 5C1 m^{4}  f + 5C0 m^{5}  f^{0}

Where m is the probability of a male kitten and f is the probability of having a female kitten with both values = 0.5

P(f) ≤ 3 =(0.3125) + (0.3125) + (0.15625) + (0.03125) = 0.8125

8 0
3 years ago
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