True. The image of a translation is always congruent to the pre-image.
Proof: every point of the pre-image is move exactly the same distance and the same direction. That means that the shape stay the same but it is just located in a different place.
Hope this helps :)
Answer:
Average rate of change = 20.2
Rate of change at the left endpoint : f' (5) = 4t = 20
Rate of change at the right endpoint : f' (5.1) = 4*5.1 = 20.4
Step-by-step explanation:
The average rate of change of the function
F(t) = 2t^2 - 1 , [ 5,5.1 ]
solution
= 
= [ 2 ( 26.01 - 25 ) / 0.1 ]
= 2.02 / 0.1 = 20.2
Rate of change at the left endpoint : f' (5) = 4t = 20
Rate of change at the right endpoint : f' (5.1) = 4*5.1 = 20.4
Answer: Choice A. (8, 4)
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Explanation:
Because x = 2y, we can replace every copy of x with 2y
Let's do so in the second equation
3x - 4y = 8
3(x) - 4y = 8
3(2y) - 4y = 8 .... x replaced with 2y; now let's isolate y
6y - 4y = 8
2y = 8
y = 8/2 ..... divide both sides by 2
y = 4
Use this y value to find x
x = 2y
x = 2*4
x = 8
So we have x = 8 and y = 4 pair together to get the answer (x,y) = (8, 4) which is choice A.
I don’t know if this correct or not but I think it’s 1,666
