Answer:
3rd option x=3, y=5
Step-by-step explanation:
If they won 55 of the games, that means they lost the rest of the 75. So,
75 - 55 = 20 games lost. To find the percentage of 20 out of 75, you set up a proportion:

where x = the percentage of games lost. Cross multiply and divide to isolate the x:

Rounded to the nearest hundredth, the Royals lost 26.667 % of their games.
Substitute 22 for x
2(22)-5
44-5
39
8+0.75x=25
0.75x=25(-8)
0.75x=17
17/0.75= 22.666
He can ride a total of 22 rides
Answer:
The equivalent expression to the given expression is ![\sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B32x%5E8y%5E%7B10%7D%7D%3D2x%5E2y%5E3%5Csqrt%5B3%5D%7B4x%5E2y%7D)
Step-by-step explanation:
The given expression is ![\sqrt[3]{32x^8y^{10}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B32x%5E8y%5E%7B10%7D%7D)
To find the equivalent expression:
![\sqrt[3]{32x^8y^{10}}=(32x^8y^{10})^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B32x%5E8y%5E%7B10%7D%7D%3D%2832x%5E8y%5E%7B10%7D%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
We may write the above expression as below:

(using square root properties)
(combining the like terms and doing multiplication )
Therefore ![\sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B32x%5E8y%5E%7B10%7D%7D%3D2x%5E2y%5E3%5Csqrt%5B3%5D%7B4x%5E2y%7D)
Therefore the equivalent expression to the given expression is ![\sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B32x%5E8y%5E%7B10%7D%7D%3D2x%5E2y%5E3%5Csqrt%5B3%5D%7B4x%5E2y%7D)