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MrRa [10]
2 years ago
6

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

Mathematics
2 answers:
Firdavs [7]2 years ago
8 0

Answers:

a = 3, b = 6, c = 5

==============================================

Explanation:

There's not much to say other that the rule we use is

\sqrt[c]{a^b} = a^{b/c}

The c is the index of the root or radical. It's the denominator of the fractional exponent b/c. Comparing terms, we see that a = 3, b = 6 and c = 5.

You could simplify the a^b portion, but it seems like your teacher doesn't want that (right now).

-----------

Side notes:

  • if c = 2, then we have a square root and often the index number isn't shown at all. So \sqrt[2]{x} = \sqrt{x}. Its only when c > 2 is when we can't drop the number, or else it'll get mistaken for a square root.
  • If c = 1, then we won't have any radical. We'll have a^(b/c) = a^b if c = 1.
Jobisdone [24]2 years ago
4 0

Answer:

a = 3, b = 6, c = 5

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tester [92]

Answer:

10.4% or 13/125

Step-by-step explanation:

5 perfect squares in the set of numbers

13 odd numbers

(5/25) x (13/25) = 0.104

0.104 x 100 = 10.4%

i hope its right

4 0
1 year ago
Hopefully that’s better :)))
mr Goodwill [35]

Answer: Top right, a rectangle has all the properties of a square

Step-by-step explanation: A rectangle does not have all the properties of a square.

8 0
2 years ago
As.
Natalka [10]

9514 1404 393

Answer:

  • 4/13 h ≈ 0.308 h
  • 22 9/13 km ≈ 22.7 km

Step-by-step explanation:

Mary and Amaruk are starting 35 -15 = 20 km apart. Their closing speed is 40 +25 = 65 km/h. The time it will take to close the gap between them is ...

  t = (20 km)/(65 km/h) = 20/65 h = 4/13 h ≈ 0.308 h

They will pass each other after 4/13 hours, about 18 minutes 28 seconds.

__

In that time, Mary will have increased her distance from Hall Beach by ...

  d = (4/13 h)(25 km/h) = 100/13 km = 7 9/13 km

Her distance from Hall Beach when she passes Amaruk will be ...

  15 km + 7 9/13 km = 22 9/13 km ≈ 22.7 km . . . . . distance from Hall Beach

6 0
3 years ago
The function f(x)=200(1.4)^t gives the approximate number of fish in a large pond after t years. Select all of the true statemen
tatyana61 [14]
I think the answer would be C
5 0
3 years ago
Two airplanes are flying in the air at the same height. Airplane A is flying east at 300mi/h and airplane B is flying north at 2
Ipatiy [6.2K]

Answer:

\frac{dAB}{dt}=340 mil/h

Step-by-step explanation:

The change of distance over time of the plain A is 300 mi/hour and 200 mi/hour for plane B. O is the point of the airport.

So, the distance from A to O AO = 90 miles and BO = 120 miles.

Now, we have a right triangle here.  We can use the Pythagorean theorem, so the distance between the planes will be:

AB^{2} =AO^{2}+BO^{2} (1)

AB =\sqrt{AO^{2}+BO^{2}}=

AB =\sqrt{90^{2}+120^{2}}=150 miles

If we take the derivative of the equation (1) we could find the change of the distance between planes.

2AB\frac{dAB}{dt}=2AO\frac{dAO}{dt}+2BO\frac{dBO}{dt}

2*150\frac{dAB}{dt}=2*90*300+2*120*200=102000 mil/h

\frac{dAB}{dt}=\frac{102000}{150*2}

Finally,

\frac{dAB}{dt}=340 mil/h

I hope it helps you!

6 0
2 years ago
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