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grandymaker [24]

3 years ago

10

Find the missing side

2 answers:

geniusboy [140]3 years ago

7 0

Answer:

Step-by-step explanation:

mr_godi [17]3 years ago

6 0

Answer:

Step-by-step explanation:

c^2 = a^2 - b^2

13^2 - 5^2 = -12

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Since the cost of cheese went up, the cost of small pizza went from $5.45 to $6.50. calculate the percent increase.

wolverine [178]

Around 19% increase.

7 0

3 years ago

Read 2 more answers

Find the domain of y= 2/3 square root of x+5-4

3241004551 [841]

Set the radicand in
√
x
−
5
x
-
5
greater than or equal to
0
0
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x
−
5
≥
0
x
-
5
≥
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Add
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x
≥
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x
≥
5
The domain is all values of
x
x
that make the expression defined.
Interval Notation:
[
5
,
∞
)
[
5
,
∞
)
Set-Builder Notation:
{
x
|
x
≥
5
}
{
x
|
x
≥
5
}
The range of an even indexed radical starts at its starting point
(
5
,
0
)
(
5
,
0
)
and extends to infinity.
Interval Notation:
[
0
,
∞
)
[
0
,
∞
)
Set-Builder Notation:
{
y
|
y
≥
0
}
{
y
|
y
≥
0
}
Determine the domain and range.

4 0

3 years ago

I DONT NEED SLEEP I NEED ANSWERS

stellarik [79]

Answer:

You asked to solve questions 3 and 5

<h3>#3</h3>

Since CD = EF,

9x - 1 = 41 - 5x
9x + 5x = 41 + 2
14x = 42
x = 3

EF = 41 - 5*3
EF = 26

<h3>#5</h3>

MN = NP as their perpendicular bisectors are of same length.

9x - 43 = 5x + 33
9x - 5x = 33 + 43
4x = 76
x = 19

mMP = 360 - (mMN + mNP)
mMP = 360 - (9*19 - 43 + 5*19 + 33)
mMP = 104

6 0

3 years ago

Jamie is riding a Ferris wheel that takes fifteen seconds for each complete revolution. The diameter of the wheel is 10 meters a

Agata [3.3K]

Answer:

The answers to the question is

(a) Jamie is gaining altitude at 1.676 m/s

(b) Jamie rising most rapidly at t = 15 s

At a rate of 2.094 m/s.

Step-by-step explanation:

(a) The time to make one complete revolution = period T = 15 seconds

Here will be required to develop the periodic motion equation thus

One complete revolution = 2π,

therefore the we have T = 2π/k = 15

Therefore k = 2π/15

The diameter = radius of the wheel = (diameter of wheel)/2 = 5

also we note that the center of the wheel is 6 m above ground

We write our equation in the form

y = $5*sin(\frac{2*\pi*t}{15} )+6$

When Jamie is 9 meters above the ground and rising we have

9 = $5*sin(\frac{2*\pi*t}{15} )+6$ or 3/5 = $sin(\frac{2*\pi*t}{15} )$ = 0.6

which gives sin⁻¹(0.6) = 0.643 = $\frac{2*\pi*t}{15}$

from where t = 1.536 s

Therefore Jamie is gaining altitude at

$\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi t}{15}) =$ 1.676 m/s.

(b) Jamie is rising most rapidly when the velocity curve is at the highest point, that is where the slope is zero

Therefore we differentiate the equation for the velocity again to get

$\frac{d^2y}{dx^2} = -5*(\frac{\pi *2}{15} )^2*sin(\frac{2\pi t}{15})$ =0, π, 2π

Therefore $-sin(\frac{2\pi t}{15} )$ = 0 whereby t = 0 or

$\frac{2\pi t}{15}$ = π and t = 7.5 s, at 2·π t = 15 s

Plugging the value of t into the velocity equation we have

$\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi t}{15}) =$ - 2/3π m/s which is decreasing

so we try at t = 15 s and we have $\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi *15}{15}) = \frac{2}{3} \pi$ m/s

Hence Jamie is rising most rapidly at t = 15 s

The maximum rate of Jamie's rise is 2/3π m/s or 2.094 m/s.

7 0

3 years ago

- Steve gathered some data and Steve gathered data and found that the z-score for his salary as compared to other managers with

aev [14]

( A) is the answer or maybe b)

6 0

3 years ago