Answer:
3
Step-by-step explanation:
Answer:
Option B. is the answer.
Step-by-step explanation:
The given question is incomplete; complete question has been given in the picture attached.
Current in the circuit at the time t is
.
Power delivered to the resistor is ![I_{0}Rsin^{2}wt](https://tex.z-dn.net/?f=I_%7B0%7DRsin%5E%7B2%7Dwt)
Where R = resistance
We have to express the power in the terms of cos2w.
Since formula to get the power in a circuit with resistance R and current I is given by
P = I²R
Therefore, power for the given circuit will be
P = ![(I_{0})^{2} Rsin^{2}wt](https://tex.z-dn.net/?f=%28I_%7B0%7D%29%5E%7B2%7D%20Rsin%5E%7B2%7Dwt)
P =
[Since sin²t =
]
P =
Therefore, Option B. will be the answer.
Step-by-step explanation:
whats the question? i dont get it?
Answer:
x + 6
Step-by-step explanation:
(f ÷ g)(x) = f(x) ÷ g(x), that is
← factorise numerator
=
← cancel the common factor (x - 9), leaving
= x + 6