Answer: B
Step-by-step explanation:
30xy + 36x^2 + 30x + 25y
= 6x(5y + 6x) + 5(6x + 5y)
= (6x + 5)(6x + 5y) Answer
A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).
<h3>Calculate the vertices of ΔA'B'C':</h3>
Given that,
ΔABC : A(-6,-7), B(-3,-10), C(-5,2)
(x,y)→(x,y-3)
The vertices are:
- A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
- B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
- C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)
Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).
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Answer:
k = -8
Step-by-step explanation:
The location of P is ...
P = (2A+B)/3 = (2·2+5, 2·1-8)/3 = (3, -2)
Putting this point into the equation for the line, we have ...
2(3) -(-2) +k = 0
8 +k = 0
k = -8
The amount invested in the first account is $9,300 while the amount invested in the second account is $8,800.
<h3>
How do we calculate the amount invested?</h3>
Let x represents the amount invested in the first account.
Therefore, we have:
Amount invested in the second account = x - 500
Interest income from first account = 3% * x = 0.03x
Interest income from second account = 5% * (x - 500) = 0.05x - 25
Total interest income = 0.03x + 0.05x - 25 = 719
Solving for x, we have:
0.08x = 719 + 25
x = 744 / 0.08
x = $9,300
Substituting for x, we have:
Amount invested in the second account = $9,300 - $500 = $8,800
Learn more about the amount invested here: brainly.com/question/24132106.
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