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faust18 [17]
3 years ago
6

Help me please please please

Mathematics
2 answers:
Grace [21]3 years ago
7 0

Answer:

2x²-2x

Step-by-step explanation:

To find the area of a rectangle, you multiply the sides together.

In this case:

x × 2x-2 = x(2x-2) = 2x²-2x

masya89 [10]3 years ago
6 0

Answer:

the area = x(2x - 2) = 2x² - 2x

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How to do this question?
marta [7]
Since you know that a square has 4 equal sides then you know the small squares are 4cm on all sides and the big squares are 9cm on all sides.

If 2 and a partial sm sq are next to a 9cm sq then knowing 4*2=8 you can figure out that the other square is split as 1cm and 3cm(1+3=4), 3cm of which is lined up with the width (4cm)of another sm sq which would equal 7cm, these 2 sm sqs line up with the unknown sq whose sides would in turn also be 7cm.

A=l*w, 7*7=49

Answer:Area=49cm^2
4 0
4 years ago
Given that x has a Poisson distribution with μ = 1.5​, what is the probability that x = 4?
storchak [24]
For given Poisson distribution, <span>μ=8.

</span>P(x)=μ^x*e^(-<span>μ)/x!
so
P(4)=1.5^4*e^(-1.5)/4!= 0.04707 approx.</span>
6 0
3 years ago
Calculala circunferencia de un círculo que tiene un radio de 6.2 cm
Agata [3.3K]
Hola!

C = 2 \pi r

C es circunferencia
r es radio

C = 2* \pi *6.2

\pi = 3.14

C = 2 * 3.14 * 6.2 = 38.94

La respuesta es 38.94
7 0
3 years ago
5y + 6 = 25 + 6 what property of equality is used
steposvetlana [31]
Addition property
6=6 then 5y+6=25+6
7 0
2 years ago
Examine this system of equations. Which numbers can be multiplied by each equation so that when the two equations are added toge
Karolina [17]

The first equation must be multiplied by 18 and second equation must be multiplied by 8

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

\frac{1}{4}x -\frac{1}{6}y = 5 --------- eqn 1

\frac{4}{5}x +\frac{3}{8}y = 10 -------------- eqn 2

Multiply the second equation by 8 both sides to remove the fraction in the variable y

8(\frac{4}{5}x +\frac{3}{8}y = 10)\\\\\frac{32x}{5} + 3y = 80 -------- eqn 3

Multiply the first equation by 18 both sides to obtain the coefficient -3 in the variable y

18(\frac{1}{4}x -\frac{1}{6}y = 5)\\\\\frac{18}{4}x -3y = 90 ---------- eqn 4

Add eqn 3 and eqn 4

\frac{32}{5}x +3y +\frac{18}{4}x -3y = 80+90\\\\\frac{32}{5}x+\frac{18}{4}x = 170

Thus the y-term is eliminated

Therefore, first equation must be multiplied by 18 and second equation must be multiplied by 8

6 0
3 years ago
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