Since you know that a square has 4 equal sides then you know the small squares are 4cm on all sides and the big squares are 9cm on all sides.
If 2 and a partial sm sq are next to a 9cm sq then knowing 4*2=8 you can figure out that the other square is split as 1cm and 3cm(1+3=4), 3cm of which is lined up with the width (4cm)of another sm sq which would equal 7cm, these 2 sm sqs line up with the unknown sq whose sides would in turn also be 7cm.
A=l*w, 7*7=49
Answer:Area=49cm^2
For given Poisson distribution, <span>μ=8.
</span>P(x)=μ^x*e^(-<span>μ)/x!
so
P(4)=1.5^4*e^(-1.5)/4!= 0.04707 approx.</span>
Addition property
6=6 then 5y+6=25+6
The first equation must be multiplied by 18 and second equation must be multiplied by 8
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
--------- eqn 1
-------------- eqn 2
Multiply the second equation by 8 both sides to remove the fraction in the variable y

Multiply the first equation by 18 both sides to obtain the coefficient -3 in the variable y

Add eqn 3 and eqn 4

Thus the y-term is eliminated
Therefore, first equation must be multiplied by 18 and second equation must be multiplied by 8