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Juliette [100K]
3 years ago
10

What are the relative frequencies, to the nearest hundredth, of the rows of the two-way table? Drag and drop the values into the

boxes to show the relative frequencies.

Mathematics
1 answer:
quester [9]3 years ago
8 0

Answer:

.25             .75

.44            .56

Step-by-step explanation:

To find the relative frequency, we take the part over the total.

Since this  is a relative frequency table, the total for each row is 1

Group 1 A  = 15/ (15+45) = 15/60 = .25

Group 1 B = 45/(15+45) = 45/60 = .75

Group 2 A = 20 /(20+25) = 20/45 =.44

Group 2B = 25/(20+25) = 25/45 =.56

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Answer:

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3 years ago
Is 4/5 greater or less than 7/12
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Which points are coplanar and noncollinear
yaroslaw [1]

Answer:

Non-collinear points: These points, like points X, Y, and Z in the above figure, don't all lie on the same line. Coplanar points: A group of points that lie in the same plane are coplanar. Any two or three points are always coplanar. Four or more points might or might not be coplanar.

Step-by-step explanation:

4 0
3 years ago
By what percent change if the numerator is decreased by 10% and the denominator is decreased by 70%
hjlf

Answer:

It increases x3.

Step-by-step explanation:

Let's say the fraction to begin with was 100/100. Ignore the fact that it isn't fully reduced and it is an improper fraction.

10% of 100 is 10, so the numerator is now 90 (decrease=get smaller; 100-10=90).

70% of 100 is 70, so the denominator is now 30 (decrease=get smaller; 100-70=30).

Our fraction is now 90/30 which, when fully reduced, equals 3.00. Since 100/100 equals 1.00, it has increased by 2.00 (3x bigger).

6 0
3 years ago
Kali invests $3516 in a savings account with a fixed annual interest rate of 7% compounded 3 times per year. What will the accou
ZanzabumX [31]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$3516\\
r=rate\to 7\%\to \frac{7}{100}\to &0.07\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{well, is just three}
\end{array}\to &3\\
t=years\to &7
\end{cases}
\\\\\\
A=3516\left(1+\frac{0.07}{3}\right)^{3\cdot 7}\implies A=3516\left( \frac{307}{300} \right)^{21}\implies A\approx 5707.0070
7 0
3 years ago
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