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SIZIF [17.4K]
3 years ago
12

Help plsFind xa(21)b(27)c(9)d(18)​

Mathematics
1 answer:
tino4ka555 [31]3 years ago
3 0

9514 1404 393

Answer:

  a.  21

Step-by-step explanation:

The external part of the hypotenuse of the right triangle is shown. The full length of the hypotenuse is 9+20 = 29. The Pythagorean theorem can be used to find x.

  x^2 +20^2 = 29^2

  x^2 = 841 -400

  x = √441

  x = 21

__

<em>Alternate solution</em>

The diameter of the circle is 2·20 = 40 units, so the product of distances from the external vertex to the opposite sides of the circle along the secant is (9)(40+9). The product of the distances along the tangent is x·x. These two products are equal, so ...

  x^2 = 9(49)

  x = (√9)(√49) = 3·7

  x = 21

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\bf Step-by-step~explanation:

Let's look at (a) first. Since -5 is in parenthesis, we have to replace x with -5. You do the same thing on (b): replace x with 2.

\bf Step~1~(a):

We have to replace x with -5.

\bf f(x)=x^2-2x\\f(-5)=(-5)^2-2(-5)\\f(-5)=25-2(-5)\\f(-5)=25+10\\f(-5)=35

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We have to replace x with 2 now.

\bf f(x)=x^2-2x\\f(2)=2^2-2(2)\\f(2)=4-2(2)\\f(2)=4-4\\f(2)=0

\large\boxed {\bf Our~final~answer:~f(-5)=35; ~f(2)=0}

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