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3 years ago

What is the value of x?

Mathematics

2 answers:

prohojiy [21]3 years ago

8 0

Answer:

x = 12 degree

Step-by-step explanation:

3x + 19 + 5x = 115 degree (sum of two interior opposite angles are equal to the third side)

8x + 19 = 115

8x = 115 - 19

x = 96 /8

x = 12

Feliz [49]3 years ago

7 0

Answer:

MARK ME BRAINLIEST THANKS MY ANSWER PLEASE

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S_A_V [24]

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8 0

2 years ago

Vertex form of <br> y=x^2-4x-9

Scrat [10]

Complete the square
first isolate x terms
y=(x^2-4x)-9
complete square inside (take 1/2 of square of b )
-4/2=-2, (-2)^2=4
add 4-4 inside
y=(x^2-4x+4-4)-9
complete the square
y=((x-2)^2-4)-9
y=(x-2)^2-4-9
y=(x-2)^2-13

3 0

3 years ago

PLEASE HELP ILL GIVE BRAINLIEST

DanielleElmas [232]

Option A:

$(x-5)^{2}+(y-3)^{2}=16$

Solution:

Given data:

Center of the circle is (5, 3).

Radius of the circle = 4

To find the equation of the circle:

The general form of the equation of a circle in centre-radius format is

$(x-h)^{2}+(y-k)^{2}=r^{2}$

where (h, k) is the centre of the circle and r is the radius of the circle.

Substitute the given values in the equation of a circle formula:

$(x-5)^{2}+(y-3)^{2}=4^{2}$

$(x-5)^{2}+(y-3)^{2}=16$

The equation of the given circle is $(x-5)^{2}+(y-3)^{2}=16$ .

Hence Option A is the correct answer.

5 0

3 years ago

To which rational number subset(s) do the following numbers belong?

Murrr4er [49]

Answer:

D. Natural Numbers, wholes, and integers.

5 0

3 years ago

Read 2 more answers

If f(x)=2−x12 and g(x)=x2−9, what is the domain of g(x)÷f(x)?

Keith_Richards [23]

$\bf \begin{cases}
f(x)=2-x^{12}\\
g(x)=x^2-9\\
g(x)\div f(x)=\frac{g(x)}{f(x)}
\end{cases}\implies \cfrac{x^2-9}{2-x^{12}}$

now, for a rational expression, the domain, or "values that x can safely take", applies to the denominator NOT becoming 0, because if the denominator is 0, then the rational turns to undefined.

now, what value of "x" makes this denominator turn to 0, let's check by setting it to 0 then.

$\bf 2-x^{12}=0\implies 2=x^{12}\implies \pm\sqrt[12]{2}=x\\\\
-------------------------------\\\\
\cfrac{x^2-9}{2-x^{12}}\qquad \boxed{x=\pm \sqrt[12]{2}}\qquad \cfrac{x^2-9}{2-(\pm\sqrt[12]{2})^{12}}\implies \cfrac{x^2-9}{2-\boxed{2}}\implies \stackrel{und efined}{\cfrac{x^2-9}{0}}$

so, the domain is all real numbers EXCEPT that one.

4 0

3 years ago