-1/2 divided by _____= -7/3 please fill in the blank

A bat and a ball cost one dollar and ten cents in total. The bat costs a dollar more than the ball. How much does the ball cost?

Nastasia [14]

The answer is 5 cents because if the bat is a dollar more, then it the bat would be $1.05, and 0.05 + 1.05 = $1.10

you could also use the equation x + (x + 1) = 1.10 where x is the cost if the ball and x + 1 is the cost of the bat. x + x + 1 is the same as 2x + 1 = 1.10, and when solved x = 0.05.

7 0

1 year ago

Best one gets brainliest please help!

andreyandreev [35.5K]

Answer: 2, 9, 14, 17, 19

Step-by-step explanation:

A box plot uses the values: minimum, maximum, median, first quartile and third quartile.

First sort the data from lowest to highest.

2,8,9,11,14,15,17,19,20

Thus, the minimum, or Data Point 1 is 2.

Then find the median.

8,9,11,14,15,17,19

9,11,14,15,17

11,14,15

14

Thus, the median, or Data Point 3 is 14.

For the 1st and 3rd quartile, simply, ignoring the median, find the median of the first and second half of the data.

8,9,11

9

Thus, the first quartile, or Data Point 2 is 9.

15,17,19

17.

Thus, the third quartile, or Data Point 4 is 17.

The maximum of the data, or Data Point 5 is 19.

4 0

3 years ago

Plzzzzzzzz help right answer gets brainly

Lelechka [254]

Answer:

A

Step-by-step explanation:

7 0

2 years ago

Marc is building a rectangular wooden frame for his canvas. If the canvas is 7 feet long by 5 feet wide, what is the perimeter o

Assoli18 [71]

Answer:

24 feet

Step-by-step explanation:

Use the perimeter formula, P = 2l + 2w, where l is the length and w is the width.

Plug in the values, and solve:

P = 2l + 2w

P = 2(7) + 2(5)

P = 14 + 10

P = 24

So, the perimeter of the canvas is 24 feet

8 0

3 years ago

Suppose a certain population satisfies the logistic equation given by dP

Ksenya-84 [330]

Answer:

The population when t = 3 is 10.

Step-by-step explanation:

Suppose a certain population satisfies the logistic equation given by

$\frac{dP}{dt}=10P-P^2$

with P(0)=1. We need to find the population when t=3.

Using variable separable method we get

$\frac{dP}{10P-P^2}=dt$

Integrate both sides.

$\int \frac{dP}{10P-P^2}=\int dt$ .... (1)

Using partial fraction

$\frac{1}{P(10-P)}=\frac{A}{P}+\frac{B}{(10-P)}$

$A=\frac{1}{10},B=\frac{1}{10}$

Using these values the equation (1) can be written as

$\int (\frac{1}{10P}+\frac{1}{10(10-P)})dP=\int dt$

$\int \frac{dP}{10P}+\int \frac{dP}{10(10-P)}=\int dt$

On simplification we get

$\frac{1}{10}\ln P-\frac{1}{10}\ln (10-P)=t+C$

$\frac{1}{10}(\ln \frac{P}{10-P})=t+C$

We have P(0)=1

Substitute t=0 and P=1 in above equation.

$\frac{1}{10}(\ln \frac{1}{10-1})=0+C$

$\frac{1}{10}(\ln \frac{1}{9})=C$

The required equation is

$\frac{1}{10}(\ln \frac{P}{10-P})=t+\frac{1}{10}(\ln \frac{1}{9})$

Multiply both sides by 10.

$\ln \frac{P}{10-P}=10t+\ln \frac{1}{9}$

$e^{\ln \frac{P}{10-P}}=e^{10t+\ln \frac{1}{9}}$

$\frac{P}{10-P}=\frac{1}{9}e^{10t}$

Reciprocal it

$\dfrac{10-P}{P}=9e^{-10t}$

$P(t)=\dfrac{10}{1+9e^{-10t}}$

The population when t = 3 is

$P(3)=\dfrac{10}{1+9e^{-10\cdot 3}}$

Using calculator,

$P=9.999\approx 10$

Therefore, the population when t = 3 is 10.

8 0

2 years ago