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3 years ago

What is the image on segment Oj rotated 270 counterclockwise around point 0?

Mathematics

1 answer:

inysia [295]3 years ago

6 0

Answer:

OL and M

Step-by-step explanation:

(1)

270° ÷ 30° = 9

Count 9 dashed lines from OJ counterclockwise, then

OJ → OL

(2)

120° ÷ 30° = 4

Count 4 dashed lines from R counterclockwise, then

R → M

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Answer:
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3 years ago

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jarptica [38.1K]

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3 years ago

The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.4 minutes and a standard deviation of 3.5

Lorico [155]

Answer:

0.6672 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 8.4 minutes

Standard Deviation, σ = 3.5 minutes

We are given that the distribution of distribution of taxi and takeoff times is a bell shaped distribution that is a normal distribution.

According to central limit theorem the sum measurement of n is normal with mean $\mu$ and standard deviation $\sigma\sqrt{n}$

Sample size, n = 37

Standard Deviation =

$=\sigma\times \sqrt{n} = 3.5\times \sqrt{37}=21.28$

P(taxi and takeoff time will be less than 320 minutes)

$P( \sum x < 320) = P( z < \displaystyle\frac{320 - 37(8.4)}{21.28}) = P(z < 0.4323)$

Calculation the value from standard normal z table, we have,

$P(\sum x < 320) =0.6672 = 66.72\%$

0.6672 is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

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3 years ago

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3 years ago

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Nat2105 [25]

Answer:

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Step-by-step explanation:

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