All categories

3 years ago

How do you graph 24x−6y=18

Mathematics

1 answer:

nikklg [1K]3 years ago

6 0

Answer:

You will graph a function with the equation being y = 4x - 3, to plot this function read step by step explanation.

Step-by-step explanation:

First we have to find the equation of the line so we do....

24x - 6y = 18

24x = 18 + 6y

6y = 24x - 18

y = 4x - 3

Now that we know the equation we just have to find two point by using this equation and connect them between each other in order to graph the function represented by this equation. For example

For x = 0

y = 4x - 3

y = -3

So we know that there is a point (0, - 3)

For x = 1

y = 4x - 3

y = 4 - 3

y = 1

So we know that there is a a point (1, 1)

Connect the two point and you will get the function graph

You might be interested in

3(2x+4)=−36 Find the variable

expeople1 [14]

Answer:

x = -8

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

(5-3)to the power of 2?

Kipish [7]

You would subtract 3 from 5 getting 2 and multiply 2 by itself getting the Answer: 4

Work: (5-3)= 2^ of 2 or 2*2 = 4

4 0

3 years ago

What number completes the sequence below? Enter your answer below.

Vsevolod [243]

They’re all adding 5, so 18+5=23

So I think 23

8 0

4 years ago

Please help me ☺️☺️☺️☺️

Alina [70]

An angle whose sides overlap to form a ray should have zero degrees

answer
zero degrees

7 0

3 years ago

Subtract rational expression. Show work please.

yan [13]

Given:

$$\frac{x+4}{x-1}-\frac{5}{x^{2}-1}$

To find:

The simplified rational expression by subtraction.

Solution:

Let us factor $x^2-1$ . It can be written as $x^2-1^2$ .

$x^2-1^2=(x-1)(x+1)$ using algebraic identity.

$$\frac{x+4}{x-1}-\frac{5}{x^{2}-1}=\frac{x+4}{x-1}-\frac{5}{(x+1)(x-1)}$

LCM of $x-1,(x+1)(x-1)=(x+1)(x-1)$

Make the denominators same using LCM.

Multiply and divide the first term by (x + 1) to make the denominator same.

$$=\frac{(x+4)(x+1)}{(x-1)(x+1)}-\frac{5}{(x-1)(x+1)}$

Now, denominators are same, you can subtract the fractions.

$$=\frac{(x+4)(x+1)-5}{(x-1)(x+1)}$

Expand $(x+4)(x+1)-5$ .

$$=\frac{x^2+4x+x+4-5}{(x-1)(x+1)}$

$$=\frac{x^{2}+5 x-1}{(x-1)(x+1)}$

$$\frac{x+4}{x-1}-\frac{5}{x^{2}-1}=\frac{x^{2}+5 x-1}{(x-1)(x+1)}$

6 0

3 years ago