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nignag [31]
3 years ago
8

Solve for z -p(d+z) = -2z+59

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
3 0

Here you go. Let me know if you have questions

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= – 1 is a solution of the equation
Nina [5.8K]

Answer:

C

Step-by-step explanation:

substitute -1 into all of the formulas, if both sides are equal, then it is correct, for C:

2(x-2)+6 = 0, sub -1

2(-1-2)+6=0, simplify and work out

2(-3)+6=0

-6+6=0

0=0

4 0
3 years ago
Simplify the equation and show work!!!!
snow_tiger [21]

Step-by-step explanation:

This is the correct answer.

Even according to calculator and working.

So not quite sure why those options are incorrect?

4 0
2 years ago
1/6 ÷ 2 = 12 (true or False)?
lilavasa [31]

Answer:

False, False, True, False, True

Step-by-step explanation:

When you divide by a whole number, the answer always come out smaller

When you divide by a fraction, the answer always come out larger

8 0
2 years ago
Let V be the volume of the solid obtained by rotating about the y-axis the region bounded y = 4x and y = x2/4 . Find V by slicin
aliya0001 [1]

Answer:

Step-by-step explanation:

Consider the graphs of the y = 4x  and  y = \frac{x^{2} }{4}.

By equating the expressions, the intersection points of the graphs can be found and in this way delimit the area that will rotate around the Y axis.

4x = \frac{x^{2} }{4} \\   x^{2}  = 16x \\ x^{2}  - 16x = 0 \\   x(x-16) = 0 then x=0  o  x=16. Therefore the integration limits are:

y = 4(0) = 0  and  y = 4(16) = 64

The inverse functions are given by:

x = 2 \sqrt{y}  and  x = \frac{y}{4}. Then

The volume of the solid of revolution is given by:

\int\limits^{64}_ {0} \, [2\sqrt{y} - \frac{y}{4}]^{2}  dy = \int\limits^{64}_ {0} \, [4y - y^{3/2} + \frac{y^{2}}{16} ]\  dy = [2y^{2} - \frac{2}{5}y^{5/2} + \frac{y^{3}}{48} ]\limits^{64}_ {0} = 546.133 u^{2}

6 0
3 years ago
Evaluate the expression below at x= 4.
Gre4nikov [31]

Suggestion:

Try to explain this more clearly.

Why you should try my suggestion:

Because it will help others so they understand what your question is.

My note:

Hoped I helped, and I would love to be marked as Brainliest! Thanks!

7 0
2 years ago
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