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lukranit [14]
2 years ago
6

Find an equation for the line parallel to 3y+6X=6 and goes through the point (-3,-7) please write in y=mx+b

Mathematics
1 answer:
seropon [69]2 years ago
5 0

Answer: y=-6x-25

Step-by-step explanation:

Find slope of original line by solving for y

3y+6x=6

y+6x=2

y = -6x+2 <--- we have found the slope is -6

Using y-y1 = m (x-x1) find the equation for the parallel line:

y-(-7)= -6(x-(-3)) <--- plug in the point coordinates and slope into the equation and solve for y

y+7=-6x-18

y=-6x-25

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three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal
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I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

=     x + x + (x + \frac{6}{5}) = \frac{27}{4}

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( let's take the LCM of 4 and 5 = 20

=     3x = \frac{135}{20} - \frac{24}{20}

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=       x = \frac{111}{20} ÷ \frac{3}{1} = \frac{111}{20} × \frac{1}{3} = \frac{37}{20}

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1st bag =     \frac{37}{20} kg

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