Answer:
9.6 square inches.
Step-by-step explanation:
We are given that ΔBAC is similar to ΔEDF, and that the area of ΔBAC is 15 inches. And we want to determine the area of ΔDEF.
First, find the scale factor <em>k</em> from ΔBAC to ΔDEF:
Solve for the scale factor <em>k: </em>
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Recall that to scale areas, we square the scale factor.
In other words, since the scale factor for sides from ΔBAC to ΔDEF is 4/5, the scale factor for its area will be (4/5)² or 16/25.
Hence, the area of ΔEDF is:
In conclusion, the area of ΔEDF is 9.6 square inches.
If you follow PEMDAS
P-parentheses
E-exponent
M-multiplication
D-divide
a-addition
s-subtraction
then you should look in the parentheses and multiplying 3x should be your first step IF you know x
hope this helps :)
Answer:
A. moving forward for 10m at a steady pace of 2m/s
B. moving backwards 8m at a steady pace of 2.67m/s
C. staying in the same spot for 4 seconds
D. moving 9m at a steady pace of 4.5m/s
E. moving 4.5m with an <u><em>average</em></u><em> </em>pace of 1.5m/s
9 5/6 - 2 1/3 is 7 1/2.
You could get this answer by finding the same denominator of the fractions. The LCM of both is 6. Multiply the 1 of the second fraction 2 times because you had to multiply the denominator 2 times to get to 6.
You should have 2 2/6.
Now get 9 5/6 - 2 2/6.
The answer is 7 3/6, simplifies into 7 1/2.
9 5/6 - 2 1/3 is 7 1/2.
