Find the equation of the line that passes through (3,-4) and is parallel to 3x+y+2=0
2 answers:
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The linear equations are y - 25 = 0.89(x - 20) and y = 0.89x + 7.2
<h3>The slope of the line</h3>The complete question is added as an attachment
The two points from the graph are (20, 25) and (38, 41)
The slope of the line is calculated using
m = (y2 - y1)/(x2 - x1)
Substitute the known values in the above equation
m = (41 - 25)/(38 - 20)
Evaluate
m =0.89
<h3>The linear equation in point slope form</h3>This is calculated as:
y - y1 = m(x - x1)
Substitute the known values in the above equation
y - 25 = 0.89 * (x - 20)
Evaluate
y - 25 = 0.89(x - 20)
<h3>The linear equation in slope-intercept form</h3>We have:
y - 25 = 0.89(x - 20)
Expand
y - 25 = 0.89x - 17.8
Add 25 to both sides
y = 0.89x + 7.2
Hence, the linear equations are y - 25 = 0.89(x - 20) and y = 0.89x + 7.2
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