3 years ago

Find the equation of the line that passes through (3,-4) and is parallel to 3x+y+2=0

Mathematics

2 answers:

miskamm [114]3 years ago

4 0

Answer:

y=-3x+5

Step-by-step explanation:

it parallel to 3x+y+2=0 => line is: 3x+y+c=0

It through (3;-4) => 3(3)+(-4)+c=0 <=> c=-5

Line is 3x+y-5=0 => y=-3x+5

g100num [7]3 years ago

3 0

Answer:

Since it’s parallel to 3x+y+2=0 then it must be of the form 3x+y+k=0. Since (3,-4) is on the line we have 0=3*3-4+k=k+5, therefore k=-5 and the equation is 3x+y-5=0

In the form y=mx+c this becomes y=-3x+5

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