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lesya [120]
3 years ago
13

Find the equation of the line that passes through (3,-4) and is parallel to 3x+y+2=0

Mathematics
2 answers:
miskamm [114]3 years ago
4 0

Answer:

y=-3x+5

Step-by-step explanation:

it parallel to 3x+y+2=0 => line is: 3x+y+c=0

It through (3;-4) => 3(3)+(-4)+c=0 <=> c=-5

Line is 3x+y-5=0 => y=-3x+5

g100num [7]3 years ago
3 0

Answer:

Since it’s parallel to 3x+y+2=0 then it must be of the form 3x+y+k=0. Since (3,-4) is on the line we have 0=3*3-4+k=k+5, therefore k=-5 and the equation is 3x+y-5=0

In the form y=mx+c this becomes y=-3x+5

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Answer:

40

Step-by-step explanation:

Angle KPJ is going to have the same measure as Angle DPE. This problem is a bit tricky, but I'll try my best to explain it. A straight angle is basically just a straight line, and it equals 180 degrees. Angle FPG is a straight angle.

To find the measure of Angle KPJ, we first have to find the measure of angle DPE, and the way we're gonna do that is add together the other angles in the straight angle (which would be Angle FPD and Angle EPG) and then subtract that from 180 (measure of a straight angle).

That might have sounded a bit confusing, but that's the best way I could explain it. Now, let's add Angle FPD and Angle EPG.

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Now, let's subtract that from 180.

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We now know that the measure of Angle DPE is 40, and since it's equivalent to Angle KPJ, our answer is 40!

I know that was confusing, but I hope it helped a little bit! Have a lovely day!! :)

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2 years ago
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NikAS [45]

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Step-by-step explanation:

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