Y-y1=m(x-x1)
m= slope =-3
y-y1=-3(x-x1),
y1=-7, x1=5
y--7=-3(x-5)
y+7=-3(x-5) this is C
Incomplete Question the complete Qs is
Which of the following is a correct equation for the line passing through the point (-2,1) and having slope m = 1/2?
a: y=1/2x+2
b: y=-2x+1/2
c: x-2y=-4
d: y-1=1/2(x+2)
Answer:
The Correct option is c. x-2y=-4
Therefore the correct equation for the line passing through the point (-2,1) and having slope m= 1/2 is
Step-by-step explanation:
Given:
point A(x₁, y₁)=(-2,1)
To Find:
Equation of Line =?
Solution:
Equation of a line passing through a points A( x₁ , y₁) and having slope m is given by the formula,
i.e equation in point - slope form
Now on substituting the slope and point A( x₁ , y₁) ≡ ( -2 , 1) we get
As required
Therefore the correct equation for the line passing through the point (-2,1) and having slope m= 1/2 is
Alright so, since it says that he eats at least $10 dollars no matter what we can basically leave that alone. next week have $3.50 for every new customer (x) so we could write this as $3.50x. and lastly we have Y the amount he will earn every week.
so the equation would be $10+$3.50x=Y.
if we had more information we might be able to solve for Y but since it doesn't tell us how many he sold we would leave it like that.
Let the side of the garden alone (without walkway) be x.
Then the area of the garden alone is x^2.
The walkway is made up as follows:
1) four rectangles of width 2 feet and length x, and
2) four squares, each of area 2^2 square feet.
The total walkway area is thus x^2 + 4(2^2) + 4(x*2).
We want to find the dimensions of the garden. To do this, we need to find the value of x.
Let's sum up the garden dimensions and the walkway dimensions:
x^2 + 4(2^2) + 4(x*2) = 196 sq ft
x^2 + 16 + 8x = 196 sq ft
x^2 + 8x - 180 = 0
(x-10(x+18) = 0
x=10 or x=-18. We must discard x=-18, since the side length can't be negative. We are left with x = 10 feet.
The garden dimensions are (10 feet)^2, or 100 square feet.
<span>The value of y when x=3 when the value of y varies directly with x^2, and y = 150 when x = 5 is 54. Since the value of y varies directly with x2, then: y = k * x^2, where k is constant. When y = 150 and x = 5, the value of constant is: 150 = k * 5^2. 150 = k * 25. k = 150/25. k = 6. Thus, when x = 3, the value of y will be: y = 6 * 3^2. y = 6 * 9. y = 54.</span>