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Cerrena [4.2K]
3 years ago
11

Pick the set of numbers which contain ALL perfect squares:

Mathematics
2 answers:
Bumek [7]3 years ago
8 0
The answer is D I believe.
alexandr1967 [171]3 years ago
6 0
The answer is D. {81,16,25,49,1}
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Express as a single power of 2
den301095 [7]
When you multiply powers, they add, and when you divide them they subtract.
So I would first add the 2^a + 2^b +2^c to get 2^(a+b+c)
Then, divide by 2^(a+b). Because when you divide powers they subtract, you will be taking away the (a+b) from the (a+b+c) and you will be left with c on its own.
The answer is 2^c
6 0
3 years ago
Help me plz now plz help me asap​
loris [4]

\\ \sf\longmapsto 0.49=\dfrac{49}{100}

\\ \sf\longmapsto 0.093=\dfrac{93}{1000}

\\ \sf\longmapsto 0.021=\dfrac{21}{1000}

\\ \sf\longmapsto 0.103=\dfrac{103}{1000}

6 0
3 years ago
it is known that the population proton of utha residnet that are members of the church of jesus christ 0l6 suppose a random samp
Lady_Fox [76]

Answer:

0.0838 = 8.38% probability of obtaining a sample proportion less than 0.5.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Proportion of 0.6

This means that p = 0.6

Sample of 46

This means that n = 46

Mean and standard deviation:

\mu = p = 0.6

s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.6*0.4}{46}} = 0.0722

Probability of obtaining a sample proportion less than 0.5.

p-value of Z when X = 0.5. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.5 - 0.6}{0.0722}

Z = -1.38

Z = -1.38 has a p-value of 0.0838

0.0838 = 8.38% probability of obtaining a sample proportion less than 0.5.

8 0
3 years ago
What is the mean absolute deviation of Robin’s scores?
My name is Ann [436]

Answer:

Step-by-step explanation:

5.2

8 0
3 years ago
Read 2 more answers
X+2(x+y)=7<br> 3(x-y)=1-2y<br><br> What is x&amp;y????<br><br><br><br> Please answer asap!!!!
Shkiper50 [21]
X= -x over 2 (negative x as a fraction and 2 is the denominator) minus y+ (seven as the numerator over 2 as the denominator).
Solve for y by simplify both sides with inverse operations, then isolate the variable and you get,  y = 3x - 1.
4 0
3 years ago
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