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Marianna [84]
3 years ago
8

Step 8: Does the direction of the graphed line correspond to the sign of the calculated slope?

Mathematics
2 answers:
slega [8]3 years ago
4 0
3rd choice i think but i could be wrong i’m kinda dumb
aleksandr82 [10.1K]3 years ago
4 0
3rd choice I believe
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What is the relationship between the number of vertices in each polygon and the number of isosceles triangles?
melisa1 [442]

no. of vertices = no. of isosceles triangle

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Which rational exponent represents a square root?
Viefleur [7K]

Answer:

1/2 rational exponent represents a square root.

Step-by-step explanation:

Because it is an example of a true square root.

7 0
2 years ago
Answer the question in the pic correctly. (best answer gets brainliest).
True [87]

Answer:

B

Step-by-step explanation:

slope of line JK= -1/11and slope of the line LM = 7/5

also is there any graph or table related to this

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3 years ago
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the base of a triangle is 8 inches more than the height. The area is 45 inches. Find the dimensions of the triangle
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3 years ago
An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from so
alexgriva [62]

Solution :

Let p_1 and p_2  represents the proportions of the seeds which germinate among the seeds planted in the soil containing 3\% and 5\% mushroom compost by weight respectively.

To test the null hypothesis H_0: p_1=p_2 against the alternate hypothesis  H_1:p_1 \neq p_2 .

Let \hat p_1, \hat p_2 denotes the respective sample proportions and the n_1, n_2 represents the sample size respectively.

$\hat p_1 = \frac{74}{155} = 0.477419

n_1=155

$p_2=\frac{86}{155}=0.554839

n_2=155

The test statistic can be written as :

$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}

which under H_0  follows the standard normal distribution.

We reject H_0 at 0.05 level of significance, if the P-value or if |z_{obs}|>Z_{0.025}

Now, the value of the test statistics = -1.368928

The critical value = \pm 1.959964

P-value = $P(|z|> z_{obs})= 2 \times P(z< -1.367928)$

                                     $=2 \times 0.085667$

                                     = 0.171335

Since the p-value > 0.05 and $|z_{obs}| \ngtr z_{critical} = 1.959964$, so we fail to reject H_0 at 0.05 level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the \text{proportion} of the seeds that \text{germinate differs} with the percent of the \text{mushroom compost} in the soil.

8 0
3 years ago
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