What are you trying to do here?
Solve the graph, or make it appear as something else?
First, we're going to take one sec (x) out so that we get:
sec (x) (2sec (x) -1 -1) = 0
sec (x) (2sec (x) -2) = 0
Then we're going to separate the two to find the zeros of each because anything time 0 is zero.
sec(x) = 0
2sec (x) - 2 = 0
Now, let's simplify the second one as the first one is already.
Add 2 to both sides:
2sec (x) = 2
Divide by 3 on both sides:
sec (x) = 1
I forgot my unit circle, so you'd have to do that by yourself. Hopefully, I helped a bit though!
Answer:
40.625%
Step-by-step explanation:
This is a very simple question.
We have to understand converting word equations to algebraic ones.
"is" means "="
"of" means "*"
So, we can write:
39 = what percent * 96
Now, we let "what percent" be "p" and solve the equation for p:
39 = P * 96
So,

Converting this decimal to percentage means multiplying by 100, so we have:
0.40625 * 100
= 40.625%
Answer:
A= T/CB - 6/B
that is the answer to the question
Answer:
- 9
Step-by-step explanation:
The average rate of change of f(x) in the closed interval [ a, b ] is

Here [a, b ] = [ - 5, 2 ], thus
f(b) = f(2) = 2² - 6(2) + 2 = 4 - 12 + 2 = - 6
f(a) = f(- 5) = (- 5)² - 6(- 5) + 2 = 25 + 30 + 2 = 57 , thus
average rate of change =
=
= - 9
Given :
A trailer will be used to transport several 40-pound crates to a store.
The greatest amount of weight that can be loaded into the trailer is 1,050 pounds.
An 82-pound crate has already been loaded onto the trailer.
To Find :
The greatest number of 40-pound crates that can be loaded onto the trailer.
Solution :
Weight left = 1050 - 80 = 970 pound.
Let, number of 40 pounds crates that can be loaded are x.

Since, crate cannot be in fraction, so maximum crate that can be loaded is 24.
Hence, this is the required solution.