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Mariulka [41]
3 years ago
8

Will mark brainliest for any help!

Mathematics
2 answers:
katrin2010 [14]3 years ago
8 0
The answer is d your welcome
jarptica [38.1K]3 years ago
5 0

Answer:

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Step-by-step explanation:

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What are the domain and range of f(x) = (1/6)x + 2? domain: ; range: {y | y > 0} domain: ; range: {y | y > 2} domain: {x |
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Sir you posted question and answer? or are providing examples of preferred format?

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Write the equation of the line in fully simplified slope intercept form
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Answer:   y = (1/4)x - 1

Step-by-step explanation:

Slope intercept form is y = mx + b. The y-intercept is -1 so we have y = mx - 1. To find m, look at the points (0, -1) and (4, 0). The line goes up 1 and over 4, so the slope, m, equals 1/4. Thus the full equation is

$y = (1/4)x - 1.

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Step-by-step explanation:

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Which of the following is the sum of the slopes of the line 3x+y=1 and a line perpendicular to this line? A 0 B 13 C −83 D −6
laiz [17]

Answer:

-8/3

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First find the slope of the line

3x+y = 1

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y = -3x+1

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y = mx+b where m is the slope

The slope is -3

The slopes of perpendicular lines multiply to -1

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The sum is -3 + 1/3

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What kind of problem do we need to use “indefinite integral” to solve? Use a real life example to explain.
anastassius [24]

Answer:

Indefinite integration acts as a tool to solve many physical problems.

There are many type of problems that require an indefinite integral to solve.

Basically indefinite integration is required when we deal with quantities that vary spatially or temporally.

As an example consider the following example:

Suppose that we need to calculate the total force on a object placed in a non- uniform field.

As an example let us consider a rod of length L that posses an charge 'q' per meter length and suppose that we place it in a non uniform electric field which is given by

E(x)=\frac{E_{o}}{e^{kx}}

Now in order to find the total force on the rod we cannot use the similar procedure as we can see that the force on the rod varies with the position of the rod.

But if w consider an element 'dx' of the rod at a distance 'x' from the origin the force on this element will be given by

dF=E(x)\times qdx\\\\dF=\frac{qE_{o}}{e^{kx}}dx

Now to find the whole force on the rod we need to sum this quantity over the whole length of the rod requiring integration, as shown

\int dF=\int \frac{qE_{o}}{e^{kx}}dx

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