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3 years ago

Solve for x. 1) 22x -2=20x+10

Mathematics

2 answers:

Ivanshal [37]3 years ago

8 0

Answer:

x=6

Step-by-step explanation:

22x-2=20x+10

22x-20x=10+2

2x=12

x=6

vlada-n [284]3 years ago

4 0

Answer:

x = 6

Step-by-step explanation:

22x - 2 = 20x + 10

+2 +2

22x = 20x + 12

-20x -20x

2x = 12

2x/2 12/2

x = 6

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For a parallelogram with a long side that is 4 times the length of its short side find the area if the height from the long side

Zielflug [23.3K]

9514 1404 393

Answer:

c. 1150 square units

Step-by-step explanation:

The sum of the two side lengths is half the perimeter, so is 125/2 = 62.5 units. The long side is 4/5 of that, so is 50 units.

The area is the product of the long side and the height to the long side:

A = bh

A = (50 units)(23 units) = 1150 units²

Additional comment

This geometry is impossible, because the height from the long side cannot be more than the length of the short side. Here, the short side is 12.5 units, so it is not possible for the height to be 23 units.

If the height is measured from the short side, then the area is 287.5 square units.

5 0

3 years ago

List the members of P(fa, b, c, d}). Which are proper subsets of fa, b,c, d)?

ankoles [38]

Answer: As i understand, the set is P = {a,b,c,d}

then all the proper subsets are all the sets that belongs to P, that are different of P. Then A is a subset of P if all the elements of A belongs to P, but A is not equal to P

this is:

the sets of one element : {a}, {b}, {c}, {d} and the null set; ∅

sets of two elements: {a,b} , {a,c} , {a.d}, {b,c}, {b,d}, {c,d}

sets of three elements : {a,b,c}, {a,b,d}, {a,c,d}, {b,c,d}

and there arent sets of 4 elements or more.

6 0

3 years ago

A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-‐

cricket20 [7]

Answer:

The final curse load of the local gym instructor is this:

High-‐impact aerobics = 1

Low-‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-‐impact aerobics, 64 wanted low-‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-‐impact aerobics = 8/14.25 = 0.5614

Low-‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-‐impact aerobics = 0

Low-‐impact aerobics = 4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-‐impact aerobics with .5614.

The final course load is this:

High-‐impact aerobics = 1

Low-‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

7 0

3 years ago

A candy store called "Sugar" built a giant hollow sugar cube out of wood to hang above the entrance to their store. It took 5454

Elina [12.6K]

Answer:

27 ft^3

Step-by-step explanation:

The total surface area of the cube is 54 ft^2.

A cube has 6 congruent square sides.

54 ft^2/5 = 9 ft^2

Each square side has area 9 ft^2.

The area of a square is the square of the side, so the side of a square is the square root of the area.

side = sqrt(9 ft)^2 = 3 ft

The volume of a cube is the cube of the side.

volume = (3 ft)^3

volume = 27 ft^3

4 0

3 years ago

Find the value of x in the diagram below.

dsp73

Answer:

x = 31

Step-by-step explanation:

The 2 sides are congruent, meaning the 2 angles are equal so:

47 = x + 16

subtract 16 from both sides

31 = x

5 0

3 years ago

Solve for x. 1) 22x -2=20x+10​

Solve for x. 1) 22x -2=20x+10