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Kipish [7]
3 years ago
6

The ________ phase of the customer relationship management process is where organizational learning occurs based on customer res

ponse to the implemented strategies and programs.
Business
2 answers:
MA_775_DIABLO [31]3 years ago
8 0

Answer: analysis and refinement

k0ka [10]3 years ago
6 0

Answer:

The<em> <u>analysis and refinement</u></em><u> </u> phase of the customer relationship management process is where organizational learning occurs based on customer response to the implemented strategies and programs.

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A major disadvantage of the payback period method is that it:_____.
netineya [11]

Answer:

C.

Explanation:

Does not directly account for the time value of money.

8 0
3 years ago
The total cost function for a product is C(x) = 850 ln(x + 10) + 1700 where x is the number of units produced. (a) Find the tota
aksik [14]

Answer:

a. $6,245.04

b. 9,605 units

Explanation:

(a) Find the total cost of producing 200 units. (Round your answer to the nearest cent.)

Given C(x) = 850 ln(x + 10) + 1700 ............................... (1)

Since x = 200 units, we substitute it into equation (1) solve as follows:

C(200) = 850 ln(200 + 10) + 1700

            = 850 ln(210) + 1700

            = 850(5.34710753071747) + 1700

            = 4,545.04140110985 + 1700

C(200) = $6,245.04

Therefore, the total cost of producing 200 units is $6,245.04.

(b) Producing how many units will give total costs of $9500? (Round your answer to the nearest whole number.) units

To do this, we simple equate equation (1) to $9500 and solve for x as follows:

850 ln(x + 10) + 1700 = 9500

850lnx + In10 = 9500 - 1700

850lnx + 2.30 = 7,800

850lnx = 7,800 - 2.30

850lnx = 7,797.70

lnx = 7,797.70 ÷ 850

lnx = 9.17

x = e^9.17

x = 9,605

Therefore, 9,605 units will give total costs of $9500.

3 0
3 years ago
Depreciation Methods On January 2, 2018, Skyler, Inc. purchased a laser cutting machine to be used in the fabrication of a part
Studentka2010 [4]

Answer:

Part A  

1. Straight-line.    

Year   Depreciation expenses ($)  

2018  228,750  

2019  228,750  

2020  228,750  

2021  228,750  

2. Double-declining balance.  

Year   Depreciation expenses ($)  

2018  460,000  

2019  230,000  

2020  115,000  

2021  110,000  

3. Units-of-production. (Assume annual production in cuttings of 200,000; 350,000; 260,000; and 110,000.)    

Year   Depreciation expenses ($)  

2018  198,913  

2019  348,098  

2020  258,587  

2021  109,402  

Part B  

1. Straight-line.    

Year   Depreciation expenses ($)  

2018  114,375  

2019  228,750  

2020  228,750  

2021  228,750  

2022  114,375  

2. Double-declining balance.  

Year   Depreciation expenses ($)  

2018  230,000  

2019  345,000  

2020  172,500  

2021  86,250  

2022  81,250  

3. Units-of-production. (Assume annual production in cuttings of 200,000; 350,000; 260,000; and 110,000.)    

Year   Depreciation expenses ($)  

2018  99,457  

2019  273,505  

2020  303,342  

2021  183,995  

2022  54,701  

Explanation:

Note: See the calculation in the attached excel file.

Download xlsx
8 0
4 years ago
Read 2 more answers
The funds dispensed at the ATM machine located near the checkout line at the Kroger's in Union Kentucky, follows a normal probab
Neporo4naja [7]

Answer:

0.00914 ; 0.0062 ; 0.9847

Explanation:

Given the following :

Normal distribution :

Mean(m) = $4200

Standard deviation (sd) = 720

Amount VERY low = < 2500

Amount very high = > 6000

a. What percent of the days will the bank be notified because the amount dispensed is very low?

x < 2500

Finding the z-score :

Z = (x - mean) / standard deviation

Z = (2500 - 4200) / 720

Z = - 1700 / 720 = −2.361111

P(z < −2.361111)

Locating −2.361111 on the z- distribution table

-2.3 under 0.06 = 0.00914

P(z < −2.361111) = 0.00914

B) What percent of the time will the bank be notified because the amount is very high?

x > 6000

Finding the z-score :

Z = (x - mean) / standard deviation

Z = (6000 - 4200) / 720

Z = 1800 / 720 = 2.5

P(z > 2.5)

Locating 2.5 on the z- distribution table = 0.9938

P(z > 2.5) = 1 - 0.9938 = 0.0062

c. What percent of the time will the bank not be notified regarding the amount of funds being dispensed?

P(2500 < X < 6000)

P(2500 < X < 6000)

P(-2.36 < z < 0) + P(0 < z < 2.5)

= 0.4909 + 0.4938

= 0.9847

7 0
3 years ago
Ken and Daisy have both applied for the job position of a dietitian at a nursing home. Both of them are equally qualified and ha
krek1111 [17]
The answer is c) staffing
6 0
3 years ago
Read 2 more answers
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