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bekas [8.4K]
3 years ago
12

If the area of a rectangle is 64cm squared, how many different perimeters are possible when the dimensions are whole numbers

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
4 0

Answer:

2 different perimeters, 32 cm and 40 cm

Step-by-step explanation:

Given the area of a rectangle is 64 cm squared.

We know, Area of the rectangle is = length x breath

∴  64 = 8 x 8

Hence the sides can be 8 cm by 8 cm.

So the perimeter of the rectangle is = 8 cm + 8 cm + 8 cm +8 cm

                                                            = 32 cm

Also, Area of the rectangle is = length x breath

∴  64 = 16 x 4

So the perimeter of the rectangle is = 16 cm + 4 cm + 16 cm +4 cm

                                                            = 40 cm  

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B) Method 2 will increase the standard deviation of the students' scores.

Step-by-step explanation:

Given that an instructor in a college class recently gave an exam that was worth a total of 100 points.

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And now he is considering two different strategies for rescaling the exam results of which:

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     3              3 - 6 = -3         -3 * -3 = 9

     5              5 - 6 = -1          -1 * -1 = 1

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Now let us suppose that we multiply each value of above data with 2 so the new data will be:

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<em>Standard Deviation of new data</em> = \sqrt{\frac{104}{3-1} } = 7.2111

<em>Hence, we see that when we multiply any value to the data the standard deviation will increase and in other words it will multiplied by that value which value we multiplied with each data value i.e. when we multiply each data value with 2 the standard deviation also get multiplied by as </em>

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