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2 years ago

If the area of a rectangle is 64cm squared, how many different perimeters are possible when the dimensions are whole numbers

Mathematics

1 answer:

FinnZ [79.3K]2 years ago

4 0

Answer:

2 different perimeters, 32 cm and 40 cm

Step-by-step explanation:

Given the area of a rectangle is 64 cm squared.

We know, Area of the rectangle is = length x breath

∴ 64 = 8 x 8

Hence the sides can be 8 cm by 8 cm.

So the perimeter of the rectangle is = 8 cm + 8 cm + 8 cm +8 cm

= 32 cm

Also, Area of the rectangle is = length x breath

∴ 64 = 16 x 4

So the perimeter of the rectangle is = 16 cm + 4 cm + 16 cm +4 cm

= 40 cm

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Elena L [17]

Answer:

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Step-by-step explanation:

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$\displaystyle V=\pi\Big[y-\frac{1}{9}y^2+\frac{1}{243}y^3\Big|_0^9\Big]$

Evaluate (I ignored the 0):

$\displaystyle V=\pi[9-\frac{1}{9}(9)^2+\frac{1}{243}(9^3)]=3\pi$

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Note:

You can do this without calculus. Notice that R₁ revolved around AB is simply a right cone with radius 1 and height 9. Then by the volume for a cone formula:

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We acquire the exact same answer.

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