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Leni [432]
3 years ago
6

Select the correct answer.

Mathematics
1 answer:
Paul [167]3 years ago
3 0
The answer should be. 5x=-12
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What is the total area of this composite figure rounded to the nearest hundredth?
weqwewe [10]

Answer:

choice #4, total=31.14 mm^2

Step-by-step explanation:

14x2=28 is area of rectangle

1^2xPi=area of small circle

3.14=area of small circle

total=31.14 mm^2

7 0
3 years ago
Please help asap 18 pts + brainliest to right/best
Diano4ka-milaya [45]

Answer:

(x-8)(x+6)

Step-by-step explanation:

Hope This Helps!!

4 0
3 years ago
Read 2 more answers
4. A rectangular back yard ice rink is to have an area of 1200m, and will be surrounded by boards. [6]
tamaranim1 [39]

Answer:

<h2>20 meters by 60 meters.</h2><h2>80 boards.</h2>

Step-by-step explanation:

We know that the ice rink is 1200 square meters, which means to enclose the rink we need dimensions of 20 meters by 60 meters, to have 1200 square meters of area.

Now, the boards are on the perimeter of the ice rink with dimensiosn 20 meters times 60 meters. So, its perimeter is

P=2(l+w)=2(60+20)=2(80)=160m

If each board is 2.0 meter long, that means we can divide to find the total number of boards we can have on the ice rink:

n=\frac{160}{2} =80

Therefore, with those dimensions, we can have 80 boards surrounding the ice rink.

7 0
3 years ago
16/9(1.2b)=4.8(20/3)<br> solve
iris [78.8K]
( b = 15.0 / le ) is the answer
6 0
3 years ago
A country's education department reported that in 2015, 70.8% of students enrolled in college or a trade school within 12 months
Gennadij [26K]

Answer:

The confidence interval has a lower limit of 0.546 and an upper limit of 0.675.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

In 2017, a random sample of 154 individuals who graduated from high school 12 months prior was selected. From this sample, 94 students were found to be enrolled in college or a trade school.

This means that n = 154, \pi = \frac{94}{154} = 0.6104

90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6104 - 1.645\sqrt{\frac{0.6104*0.3896}{154}} = 0.546

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6104 + 1.645\sqrt{\frac{0.6104*0.3896}{154}} = 0.675

The confidence interval has a lower limit of 0.546 and an upper limit of 0.675.

6 0
3 years ago
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