You can solve this by using the system of equations.
Jan - 4.95 = 2H + 3C
Wayne - 5.45 = 3H + 2C
Use elimination.
-3(2H + 3C = 4.95)
2(3H + 2C = 5.45)
Solve. And you'll get:
-6H + (-9C) = -14.85
6H + 4C = 10.9
Cross out -6H and 6H because they cancel out. And you're left with:
-9C = -14.85
4C = 10.9
Add -9C with 4C, and -14.85 with 10.9.
-5C = -3.95
Divide each side with -5.
C = $0.79
Now to figure out what H is, just substitute the C in one of the equations with 0.79.
5.45 = 3H + 2(0.79)
5.45 = 3H + 1.58
-1.58 -1.58
3.87 = 3H
3.87/3 = 3/3(H)
1.29 = H
Finished!
Answer:
Binomial
Step-by-step explanation:
Edited to add:
It can also be called a binomial because there are 2 unlike terms x and y. I'm not sure what you are studying, so it may be better to go with binomial. The Quartic is when you are looking at the degree of a single term polynomial.
You can name a polynomial based on terms, or based on degrees.
If it's based on degree it would be bi-quadratic, because it's ^4 and you have 2 different terms. If you're looking at terms it would be binomial because you have x and y to solve for.
The degree of terms is a major deciding factor whether an equation is homogeneous or not. A polynomial of more that one variable is said to be homogeneous if the degree of each term is the same. For example, 2x^7+5x^5y^2-3x^4y^3+4x^2y^5 is a homogeneous polynomial of degree 7 in x and y.
You have a 4 term polynomial with 2 variables x and y. The highest degree in your equation is 5 (4 + 1 from the first term) so the degree of the multivariable polynomial expression is 6.
All these answers are correct, it just depends what you're studying. If some of these words are new, and others you recognize from class or your book, go with the one that looks familiar.
Answer: I believe its Option 2
Step-by-step explanation: Sory if im wrong
It's the relation between the arc length of a circle, and the measure of angle. Before radians, we could only measure in degrees, and use pi to convert from arc length and circumference and angle measure. But, with the introduction of radians, it's much easier to map the relation. Hope it helps!
