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Crank
2 years ago
11

1. MONEY Maria earns $16.50 an hour working as a barista at

Mathematics
1 answer:
Inessa [10]2 years ago
7 0
$16.50 x H = total money earned
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Peter uses unit cubes to build a figure in the shape of the letter X what is the fewest unit cubes that Peter can use to build t
lozanna [386]
I am not sure I am right but I think it depends on the size of the X.

4 0
3 years ago
Describe how you can tell that a fraction corresponds to a repeating decimal and not a terminating decimal
horrorfan [7]
When a fraction corresponds to a repeating decimal, it's denominator is 9 or 99.

For example, 4/11 = 36/99 = 0.36 with bar notation over 36.

Example #2: 2/3 = 6/9 = 0.666....
or also written as 0.6 with bar notation over 6.

You know a fraction responds to a terminating decimal because it can be simplified to a terminating decimal.

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8 0
3 years ago
Solve the equation by finding square roots. x2-1/4=0
Serjik [45]

Answer:

x = ±1/2

Step-by-step explanation:

x^2-1/4=0

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x^2 -1/4+1/4 = 0+1/4

x^2 = 1/4

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6 0
2 years ago
What is 5.5x + 1−(1.5x+17)?
mrs_skeptik [129]

Answer:

4x - 16

Step-by-step explanation:

5.5x + 1 - (1.5x + 17)

5.5x + 1 -1.5x -17

Combine like terms

4x + 1 -17

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7 0
3 years ago
Read 2 more answers
4 Suppose you throw a dart at a circular target of radius 10 inches. Assuming that you hit the target and that the coordinates o
Lady bird [3.3K]

Answer:

0.04,0.25.0.52

Step-by-step explanation:

Given that you throw a dart at a circular target of radius 10 inches.

Assuming that you hit the target and that the coordinates of the outcomes are chosen at random,

probability that the dart falls

(a) within 2 inches of the center

Here favourable region has area of a circle with radius 2 inches and sample space has area of 10 inches

Prob = \frac{\pi *2^2}{\pi *10^2} \\\\=\frac{1}{25}

(b) within 2 inches of the rim.

For within two inches from the rim we have to select area of the ring i.e. area of big circle with 10 inches - area of smaller circle with 10-2 inches

Prob= \frac{\pi * *8^2}{\pi*10^2} \\=0.64

c) within I quadrant

area of I quadrant / area of circle=0.25

d) within I quadrant and within 2 inches of the rim

= I quadrant area + 2 inches ring area - common area

= \frac{\pi*10^2/4 + pi*(10^2-8^2) - \pi(10^2-8^2)/4}{\pi*10^2} \\=\frac{25+36-9}{100} \\=0.52

3 0
3 years ago
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