Answer:
Step-by-step explanation:
I think the only way you can solve this is to assume that <R means PRT in the given ratio. If I am wrong, I don't think the problem can be solved.
Find <T
Let <T = x
and <PRT = 3x
KLMN is a Parallelagram and therefore two adjacent angles are supplementary.
<PRT + <T = 180 degress
3x + x = 180 degrees
4x = 180
x = 45
So <T = 45
<PRT = 3*45 = 135
If RD is perpendicular to PS then <PDR = 90o
Here's the trick.
RD is also Perpendicular to RT
<MRD + <MRT = 90
<MRT = 180 - 90 - <T
<MRT = 180 - 90 - 45
<MRT = 45
Here comes your answer
=================
<MRD + MRT = 90
<MRD + 45 = 90
<MRD = 45
====================
Note: you must ignore everything to do with the diagram. It is not drawn to scale and the letters are not the same as in the question. The only thing you use is that the figure is a ||gm
Answer:
18.6 months
Step-by-step explanation:
Given that :
Best fit line from scatterplot :
y=-12.05x +224.26
x = Number of month
y = charge on battery
Number of months a typical battery uses before being dead completely :
When battery is dead completely ; charge =0, y = 0
y = -12.05x + 224.26
0 = - 12.05x + 224.26
12.05x = 224.26
x = 224.26 / 12.05
x = 18.610788
Hence, 18.6 months before battery is completely dead.
Answer:
0.28cm/min
Step-by-step explanation:
Given the horizontal trough whose ends are isosceles trapezoid
Volume of the Trough =Base Area X Height
=Area of the Trapezoid X Height of the Trough (H)
The length of the base of the trough is constant but as water leaves the trough, the length of the top of the trough at any height h is 4+2x (See the Diagram)
The Volume of water in the trough at any time


=8h(8+2x)
V=64h+16hx
We are not given a value for x, however we can express x in terms of h from Figure 3 using Similar Triangles
x/h=1/4
4x=h
x=h/4
Substituting x=h/4 into the Volume, V


h=3m,
dV/dt=25cm/min=0.25 m/min

=0.002841m/min =0.28cm/min
The rate is the water being drawn from the trough is 0.28cm/min.
Answer: Height of tree = 26 ft
Make a triangle ABC with 40 degrees angle. The shadow is the base of the triangle equals 31 feet.
Base = AC = 31
Perpendicular = CB = ?
Hypotenuse = AB
Using trigonometric equation
tan 40 (deg) = CB / AC
CB = Tan 40 x AC
CB = 0.83909 x 31
CB = 26.011
Thus the height of the tree = 26 ft