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Klio2033 [76]
3 years ago
11

Find the distance between the points (2,4) and (5,0). (PLEASE HELP!)

Mathematics
2 answers:
Inessa05 [86]3 years ago
5 0

Answer:

5

Step-by-step explanation:

Calculate the distance d using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (2, 4) and (x₂, y₂ ) = (5, 0)

d = \sqrt{(5-2)^2+(0-4)^2}

  = \sqrt{3^2+(-4)^2}

  = \sqrt{9+16} = \sqrt{25} = 5

frozen [14]3 years ago
3 0

The answer is:

5

Hoped I helped

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Please help me solveeeee
elena-14-01-66 [18.8K]

Answer:

Step-by-step explanation:

I think the only way you can solve this is to assume that <R means PRT in the given ratio. If I am wrong, I don't think the problem can be solved.

Find <T

Let <T = x

and <PRT = 3x

KLMN is a Parallelagram and therefore two adjacent angles are supplementary.

<PRT + <T = 180 degress

3x + x = 180 degrees

4x = 180

x = 45

So <T = 45

<PRT = 3*45 = 135

If RD is perpendicular to PS then <PDR = 90o

Here's the trick.

RD is also Perpendicular to RT

<MRD + <MRT = 90

<MRT = 180 - 90 - <T

<MRT = 180 - 90 - 45

<MRT = 45

Here comes your answer

=================

<MRD + MRT = 90

<MRD + 45 = 90

<MRD = 45

====================

Note: you must ignore everything to do with the diagram. It is not drawn to scale and the letters are not the same as in the question. The only thing you use is that the figure is a ||gm

8 0
3 years ago
Dana bikes 10 mi in 50 min.<br> <br> <br> <br> At this rate, how far can she bike in 90 min?
lara31 [8.8K]
The answer will be 18 miles
8 0
2 years ago
Read 2 more answers
A company tests the life of its rechargeable batteries over six months of use. They test how long a battery will last after a fu
jonny [76]

Answer:

18.6 months

Step-by-step explanation:

Given that :

Best fit line from scatterplot :

y=-12.05x +224.26

x = Number of month

y = charge on battery

Number of months a typical battery uses before being dead completely :

When battery is dead completely ; charge =0, y = 0

y = -12.05x + 224.26

0 = - 12.05x + 224.26

12.05x = 224.26

x = 224.26 / 12.05

x = 18.610788

Hence, 18.6 months before battery is completely dead.

4 0
2 years ago
A horizontal trough is 16 m long, and its end are isosceles trapezoids with an altitude of 4 m, a lower base of 4 m, and an uppe
Ganezh [65]

Answer:

0.28cm/min

Step-by-step explanation:

Given the horizontal trough whose ends are isosceles trapezoid  

Volume of the Trough =Base Area X Height

=Area of the Trapezoid X Height of the Trough (H)

The length of the base of the trough is constant but as water leaves the trough, the length of the top of the trough at any height h is 4+2x (See the Diagram)

The Volume of water in the trough at any time

Volume=\frac{1}{2} (b_{1}+4+2x)h X H

Volume=\frac{1}{2} (4+4+2x)h X 16

=8h(8+2x)

V=64h+16hx

We are not given a value for x, however we can express x in terms of h from Figure 3 using Similar Triangles

x/h=1/4

4x=h

x=h/4

Substituting x=h/4 into the Volume, V

V=64h+16h(\frac{h}{4})

V=64h+4h^2\\\frac{dV}{dt}= 64\frac{dh}{dt}+8h \frac{dh}{dt}

h=3m,

dV/dt=25cm/min=0.25 m/min

0.25= (64+8*3) \frac{dh}{dt}\\0.25=88\frac{dh}{dt}\\\frac{dh}{dt}=\frac{0.25}{88}

=0.002841m/min =0.28cm/min

The rate is the water being drawn from the trough is 0.28cm/min.

3 0
3 years ago
At a certain time of day, the angle of elevation is 40°. To the nearest foot, find the height of a tree whose shadow is 31 feet
elena-s [515]

Answer: Height of tree = 26 ft

Make a triangle ABC with 40 degrees angle. The shadow is the base of the triangle equals 31 feet.

Base = AC = 31

Perpendicular = CB = ?

Hypotenuse = AB

Using trigonometric equation

tan 40 (deg) = CB / AC

CB = Tan 40 x AC

CB = 0.83909 x 31

CB = 26.011

Thus the height of the tree = 26 ft

7 0
2 years ago
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