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Nady [450]
3 years ago
13

2 as rare percent is​

Mathematics
1 answer:
Vesna [10]3 years ago
4 0

Answer:

what are you asking? Because I probably have the answer

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Auto-Check Motors charged Mr. Jones $84.00 for an automotive part plus $68.00 per hour that a mechanic worked to install the par
avanturin [10]

You're going to want to take the total, which is $353.00 and subtract the initial cost, which is $84.00, the number now should be $269. Using that total divide it by $68.00, there you should find your answer of about 4 hours. The precise answer is 3.99588235. But you would round that to 4 hours.

5 0
3 years ago
4(x-6)&lt;-2x+6 what is the solution to the inequality <br> _
Cloud [144]
Simplify both sides if needed. The left-hand side needs simplification.

4(x - 6) \leq -2x + 6
4x - 24 \leq  -2x + 6

All is left to do is add and subtract to get the x variable all alone.

4x - 24  \leq -2x + 6
6x - 24  \leq  6    <-- Add 2x to both sides
6x         \leq  30  <-- Add 24 to both sides 
x           \leq 5    <-- Divide both sides by 6

In order to be in the solution set, x has to be less than or equal to 5.

In interval notation: [5, -∞)
7 0
3 years ago
Please can u help me
Andreas93 [3]

Step-by-step explanation:

multiply length, width, and height

6x4x6 and 7x4x6

First line: <u>144cm</u>

Second line: <u>168cm</u>

and those are the answers

4 0
2 years ago
Read 2 more answers
A bowl in the shape of a hemisphere has a volume of 144π cubic centimeters. What is the radius of the bowl?
Alla [95]

Answer:

6 = r

Step-by-step explanation:

V = \frac{2}{3}πr³                Use this equation to find the volume of a hemisphere

144π = \frac{2}{3}πr³           Divide both sides by \frac{2}{3}π

216 = r³                 Take the cube root of both sides

6 = r

If this answer is correct, please make me Brainliest!

6 0
3 years ago
The statement below describes a situation in which opposite quantities combine to make 0. Is the statement true or false?
Lerok [7]
True

1/2 (up the hill) - 1/2 (down the hill) = 0
6 0
3 years ago
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