Answer:
Look at the proof down
Step-by-step explanation:
The given is;
→ ∠1 and ∠2 form a linear pair
→ ∠1 ≅ ∠3
We want to prove;
→ ∠2 and ∠3 are supplementary
<em>We will write the proof in like a table</em>
1. ∠1 and ∠2 formed a linear pair ⇒ 1. Given
2. m∠1 + m∠2 = 180° ⇒ 2. Sum of angles on a straight line
3. ∠1 and ∠2 are supplementary angles ⇒ 3. Supplementary angles add up to 180°
4. ∠1 ≅ ∠3 ⇒ 4. Given
5. m∠2 + m∠3 = 180° ⇒ 5. Substitution method
6. ∠3 is a supplement of ∠2 ⇒ 6. Supplement of equal angles
7. ∠2 and ∠3 are supplementary ⇒ 7. Proved
Answer:
5n-9
Step-by-step explanation:
Answer:
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Step-by-step explanation:
