If the radius is increased by 50 per cent,
then R = r+ r/2
= 3r/2 = 1.5r
thus, increase in circumference = 2 pi r = 2 x pi x 1.5 r
= 3 pi r.
Thus initial c = 2 pi r, final c = 3 pi r.
thus increase percent = change in c/ initial c x 100 = 1/2 x 100 = 50 percent.
Thus, the circumference will also increase by 50 %
She works 5 days a week and 60% to
Answer:
Step-by-step explanation:
From the picture attached,
In ΔNMR and ΔOQP,
NM║OQ, and MP is the transversal intersecting these lines at M and Q.
∠NMR ≅ ∠OQP [Given]
m∠NRM = m∠OPQ = 90° [Given]
ΔNMR ~ ΔOQP [By AA property of similarity]
Therefore, corresponding sides of the similar triangles will be proportional.
Since, NM ≅ OQ [Given]
Therefore, NR ≅ OP
Answer:
Domain is all real Numbers
Range is all numbers over 0 - (0,
∞
)
Explanation:
One thing that you have to remember is that when you are finding the domain of a polynomial, it is all real number. it runs from
(
−
∞
,
∞
)
For finding the range, in a quadratic formula, you have to find when the finction has it's vertex. That is the place that the max or min happens and then you can find the range from there.
in this situaltion we found that the vertex is at the the origin at (0,0)
therefore the range is (0,
∞
)
No. All segments have one perpendicular bisector.