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Marrrta [24]
2 years ago
9

Helloo i need help filling out the these blanks xx

Biology
2 answers:
m_a_m_a [10]2 years ago
6 0
Try searching of for a calculator because yeah -
Sav [38]2 years ago
4 0

I was gonna try to help but then i realized i need help on the same question l m ao   Explanation:

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A nonspecific response of the body to any demand put upon it that can be both physical and mental is called
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Stress<span>A nonspecific response of the body to any demand put upon it that can be both physical and mental</span>
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3 years ago
27) C.H.20+60, + ADP + P &gt; 600, + Molecule A + ATP<br> What is molecule A in the formula above
almond37 [142]

Answer:Glycolysis: (p. 94; Fig. 6.7A-C)

Refers to:

Occurs:

Energy investment phase: Steps 1 – 4 C-C-C-C-C-C

2 ATP

How many ATP's required (used)?

Results in 2 molecules of 3 phosphoglyceraldehyde (G3P) C-C-C C-C-C

Note: Step 5 is an isomeration step between G3P & Dihydixyacetone phosphate

Energy yielding phase: Steps 6 – 10 (G3P) C-C-C C-C-C

Explanation:

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3 years ago
Tissue Description (color, texture, etc.) Tissue it attaches to
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Muscles.

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5 0
3 years ago
A record turntable is rotating at 33 rev/min. A watermelon seed is on the turntable 7.8 cm from the axis of rotation. (a) Calcul
Novosadov [1.4K]

Given data:

● Angular velocity of the turntable ω = 33 rev/min

Therefore,

ω = 33 rev/min

ω = 33rev/min × 2π rad/rev × 1 min/60 sec = 3.45 rad/s

● The distance of the watermelon seed from the axis of rotation r = 7.8 cm = 0.078 m

● μs = the coefficient of static friction

Section a:

The seed is undergoes circular motion and it is been effected by centripetal acceleration.

ac = rω^2

ac = 0.078 × 3.45^2

ac = 0.9284 m/s^2

Therefore,

the centripetal acceleration of the seed is 9.274 m/s^2

Section b:

If the seed is observed not to slip at the course of the circular motion, then the supplied frictional force given by the seed and surface of turntable would at least be equivalent to the centripetal force working on the seed.

Centripetal Force = Frictional Force

mrω^2 = μsmg

μs = rω^2 /g

μs = 0.078 × 3.45^2

------------

9.81

μs = 0.09464

Thus,

the coefficient of static friction is 0.09464.

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2 years ago
One kind evidence that supports Wagner's hypothesis is that
anyanavicka [17]

Answer:

Wegener used evidence of climate change to support his hypothesis

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