Answer:
The parents would have brown eyes.
Explanation:
Given Bb x Bb, this tells you that both parents have brown eyes and are carriers for a reccessive trait (blue eyes). Remember that the uppercase letters are considered dominant and the lower case letters are considered recessive. In order for the blue eye allele to show, you would need to have the genotype: bb.
<span>is a distinct central organelle that contains the cell's general material in the form of DNA</span>
The answer is 0.43
To calculate p we will use one of two formulas of the <span>Hardy-Weinberg principle:
</span>
p² + 2pq + q² = 1 and <u>p
+ q = 1</u>
where:
p - the frequency of the allele for long legs which is a dominant trait.
q - the frequency of the allele for short legs which is a recessive trait.
p² - the frequency of dominant homozygote (with long legs)
2pq - the frequency of heterozygote (with long legs)
q² - the frequency of recessive homozygote (with short legs)
So, 33 of 100 organisms have short legs. The frequency of recessive homozygote is represented by q²:
<span>q² = 33/100 = 0.33</span>
⇒ q = √0.33 = 0.57<span>
</span>
Using the formula:
p + q = 1
p = 1 - q = 1 - 0.57 = 0.43
Therefore, p = 0.43
Lignite. It’s a formation of coal.