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2 years ago

What is the area of the triangle? 15 18 units?

Mathematics

1 answer:

makvit [3.9K]2 years ago

4 0

Answer:

135

Step-by-step explanation:

u multiply 18 by 15 then divide the answer by 2 and I got 135 :)

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Find the value of x/y if (3/5)^4*(15/10)^4=x/y^4

scoray [572]

Answer:

9/10

Step-by-step explanation:

3^4/5^4 × 15^4/10^4=x^4/y^4

81/625 × 50625/10000= x^4/y^4

multiply

4100625/6250000=x^4/y^4

break it down by dividing it by 5

820125/1250000

divide by 5

164025/250000

divide by 5

32805/50000

divide by 5

6561/10000 = x^4/y^4

4√6561/4√10000=x/y

9/10= x/y

7 0

2 years ago

A Geiger counter counts the number of alpha particles from radioactive material. Over a long period of time, an average of 14 pa

UkoKoshka [18]

Answer:

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Over a long period of time, an average of 14 particles per minute occurs. Assume the arrival of particles at the counter follows a Poisson distribution. Find the probability that at least one particle arrives in a particular one second period.

Each minute has 60 seconds, so $\mu = \frac{14}{60} = 0.2333$

Either no particle arrives, or at least one does. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . So

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-0.2333}*(0.2333)^{0}}{(0)!} = 0.7919$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7919 = 0.2081$

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

8 0

3 years ago

Why is 743 a prime number

bonufazy [111]

743 is a prime number because it has no other positive divisors besides one and itself.

7 0

2 years ago

Help plz giving out brianlest

svet-max [94.6K]

I don’t think it is a function because you can’t have two 0’s on the Y axis it doesn’t work

4 0

2 years ago

The mpg (miles per gallon for a certain compact car is normally distributed with a mean of 31 and a standard deviation of 0.8. w

lesantik [10]

For this Q:

mean=31
st.dev.=0.8
x=32

Calculate z-score:
z=(x-m)/s = (32-31)/0.8=1.25

This z-score value corresponding to the probability of 0.8944

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6 0

2 years ago