The answer should be 95% I hope this helps :)
Answer:
$144.70
Step-by-step explanation:
Calculation to determine how much greater will the amount of interest capitalized be than the minimum amount that she could pay to prevent interest capitalization
First step is to determine the Interest only monthly repayments
Using this formula
I=Prt
where,
P=$6925
r=0.05/1
t=1
Let plug in the formula
I=6925*0.05/12
I= $28.854166666
Second step is to determine the amount she will owe after 4 years
Using this formula
S=P(1+r)n
Let plug in the formula
S=6925*(1+0.05/12)4*12
S=6925*(1+0.05/12)48
S=$8454.70
Third step is to determine the Interest part
Interest =8454.70 - 6925
Interest = $1529.70
Now let determine the how much greater will the amount of interest capitalized be
Interest capitalized=1529.70 - 1385.00
Interest capitalized =$144.70
Therefore how much greater will the amount of interest capitalized be than the minimum amount that she could pay to prevent interest capitalization is $144.70
The area of the trapezoid is calculated through the equation,
A = 0.5(b₁ + b₂)h
where A is area, b₁ and b₂ are the lengths of the bases and h is the height. Substituting the known values,
A = 0.5(15 m + 19 m)(10 m)
A = 170 m²
The area of the garden is 170 m².
Answer:
segment BC is located at B (1, 0) and C (1, 3) and is one-half the size of segment B C .
Answer: 
Step-by-step explanation:
Given
Cost per student in the year 1978 is $2200
The cost increases to $10,300 in 2008
Suppose 
is the linear equation defining the cost per student after x years
Substitute the value for 1978
After 30 years it becomes
Thus, the linear equation becomes
