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Alex Ar [27]
3 years ago
12

Select all of the possibilities for the number of solutions of a two variable linear system

Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
5 0

Select all of the possibilities for the number of solutions of a two-variable linear system.

YES no solutions

YES 1 solution

NO 2 solutions

YES infinite solutions

NNADVOKAT [17]3 years ago
4 0

Answer:

1, 2 and 4

if parrallel lines: no solution

Step-by-step explanation:

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Which one of these methods finds the volume of the given figure?? Please Help Me Asap!!!!!
mrs_skeptik [129]

Answer:

It is the second option B

Step-by-step explanation:

right

4 0
3 years ago
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In monitoring lead in the air after the explosion at the battery factory, it is found that the amounts of lead over a 7 day peri
Andrew [12]

Answer:

MOE=\pm \ 1.41

Step-by-step explanation:

-Given that \sigma=1.91, n=7

-We determine the z-value corresponding to the 95% confidence level:

z_{\alpha/2}=z_{0.025}=1.96

-The margin of error is the degree of error from the real value and is calculated as follows:

MOE=\pm z_{\alpha/2} (\frac{\sigma}{\sqrt{n}})\\\\=\pm z_{0.025}\times\frac{\sigma}{\sqrt{n}}\\\\=\pm 1.96\times \frac{1.91}{\sqrt{7}}\\\\=\pm 1.41

Hence, the margin of error is \pm 1.41

7 0
3 years ago
If y=4x - 1, find the value of y<br>when x = -2 (please help)​
yKpoI14uk [10]

Answer:

7

Step-by-step explanation:

x = - 2

y = 4x - 1

= 4 ( 2 ) - 1

= 8 - 1

y = 7

6 0
2 years ago
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Margo wants to convince her father to change her curfew from 9 P.M. to 10 P.M. She gathers data on curfew times from a random sa
Irina-Kira [14]

Answer: No; Most students have a curfew of 9 pm or earlier

3 0
3 years ago
How heavy a load (pounds) is needed to pull apart pieces of wood 4 inches long and 1.5 inches square? Here are data from student
statuscvo [17]

Answer:

a. (29526.192 , 32155.808)

b. (29673.9301 , 32008.0699)

Step-by-step explanation:

on calculation, we find that sample mean = 30843 and sample standard deviation = 3018.504, and n=20

1)

Sample Mean = 30841

SD = 3000

Sample Size (n) = 20

Standard Error (SE) = SD/root(n) = 670.8204

alpha (a) = 1 - 0.95 = 0.05

z critical value for 95% confidence interval:

z(a/2) = z(0.025) = 1.96

Margin of Error (ME) = z(a/2) x SE = 1314.808

95% confidence interval is given by:

Sample Mean +/- (Margin of Error) = 30841 +/- 1314.808

= (29526.192 , 32155.808)

2)when std dev of population is not known, we use sample's, but we have to use t instead of z

Sample Mean = 30841

SD = 3018.504

Sample Size (n) = 20

Standard Error (SE) = SD/root(n) = 674.958

alpha (a) = 1-0.9 = 0.1

we use t-distribution as population standard deviation is unknown

t(a/2, n-1 ) = 1.7291

Margin of Error (ME) = t(a/2,n-1)x SE = 1167.0699

90% confidence interval is given by:

Sample Mean +/- (Margin of Error)

30841 +/- 1167.0699 = (29673.9301 , 32008.0699)

4 0
3 years ago
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