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Alex Ar [27]
3 years ago
12

Select all of the possibilities for the number of solutions of a two variable linear system

Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
5 0

Select all of the possibilities for the number of solutions of a two-variable linear system.

YES no solutions

YES 1 solution

NO 2 solutions

YES infinite solutions

NNADVOKAT [17]3 years ago
4 0

Answer:

1, 2 and 4

if parrallel lines: no solution

Step-by-step explanation:

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Using the given zero, find one other zero of f(x). Explain the process you used to find your solution.
IRISSAK [1]

Answer:

One other zero is 2+3i

Step-by-step explanation:

If 2-3i is a zero and all the coefficients of the polynomial function is real, then the conjugate of 2-3i is also a zero.

The conjugate of (a+b) is (a-b).

The conjugate of (a-b) is (a+b).

The conjugate of (2-3i) is (2+3i) so 2+3i is also a zero.

Ok so we have two zeros 2-3i and 2+3i.

This means that (x-(2-3i)) and (x-(2+3i)) are factors of the given polynomial.

I'm going to find the product of these factors (x-(2-3i)) and (x-(2+3i)).

(x-(2-3i))(x-(2+3i))

Foil!

First: x(x)=x^2

Outer: x*-(2+3i)=-x(2+3i)

Inner:  -(2-3i)(x)=-x(2-3i)

Last:  (2-3i)(2+3i)=4-9i^2 (You can just do first and last when multiplying conjugates)

---------------------------------Add together:

x^2 + -x(2+3i) + -x(2-3i) + (4-9i^2)

Simplifying:

x^2-2x-3ix-2x+3ix+4+9  (since i^2=-1)

x^2-4x+13                     (since -3ix+3ix=0)

So x^2-4x+13 is a factor of the given polynomial.

I'm going to do long division to find another factor.

Hopefully we get a remainder of 0 because we are saying it is a factor of the given polynomial.

                x^2+1

              ---------------------------------------

x^2-4x+13|  x^4-4x^3+14x^2-4x+13                    

              -( x^4-4x^3+ 13x^2)

            ------------------------------------------

                                 x^2-4x+13

                               -(x^2-4x+13)

                               -----------------

                                    0

So the other factor is x^2+1.

To find the zeros of x^2+1, you set x^2+1 to 0 and solve for x.

x^2+1=0

x^2=-1

x=\pm \sqrt{-1}

x=\pm i

So the zeros are i, -i , 2-3i , 2+3i

7 0
3 years ago
Ronnie wants to put 1/12 of a pound of bird seed in each of the bird cages. He has 2/3 of a pound of bird seed left to use. How
Maslowich

Answer:

8

Step-by-step explanation:

2/3 / 1/12

flip sign and 2nd number

2/3 x 12/1

=8

3 0
3 years ago
I need help it due today
Alisiya [41]

Answer:

1st box: Asso. prop= m+(4+x)

2nd box: Comm. Prop= m+4=4+m

3rd box: iden. prop= m+0=m

4th box: Zero prop: m x 0=0

4 0
3 years ago
WHAT IS 24 DIVIDED BY 48 WITH WORK PLEASE
kotegsom [21]
So,

\frac{24}{48}

Write in prime factored form.
\frac{2*2*2*3}{2*2*2*2*3}

Cross-cancel
\frac{1}{2}
7 0
3 years ago
Read 2 more answers
Use a net to find the total surface of the prism.
elixir [45]

Answer:

6682.5cm

Step-by-step explanation:

29+6.5=35.5+19=54.5+1,726=1,780.5+1121=2901.5+2671=5572.5+1110=6682.5

7 0
3 years ago
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