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Alex Ar [27]
3 years ago
12

Select all of the possibilities for the number of solutions of a two variable linear system

Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
5 0

Select all of the possibilities for the number of solutions of a two-variable linear system.

YES no solutions

YES 1 solution

NO 2 solutions

YES infinite solutions

NNADVOKAT [17]3 years ago
4 0

Answer:

1, 2 and 4

if parrallel lines: no solution

Step-by-step explanation:

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How do I solve this 2 step equationn?<br> y/6 - 7 = 4
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If 10000 is invested at an interest rate of 10 per year ,compound semiannually,find the value of the investment after the given
slega [8]

Answer:

Part a) \$17,958.56  

Part b) \$32,251.00  

Part c) \$57,918.16

Step-by-step explanation:

<u><em>The complete question is</em></u>

If $10,000 is invested at an interest rate of 10% per year, compounded semiannually, find the value of the investment after the given number of years. (Round your answers to the nearest cent.)

a)6 years

b)12 years

c)18 years

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

Part a) 6 years

we have  

t=6\ years\\ P=\$10,000\\ r=10\%=10/100=0.10\\n=2  

substitute in the formula above  

A=10,000(1+\frac{0.10}{2})^{2*6}  

A=10,000(1.05)^{12}  

A=\$17,958.56  

Part b) 12 years

we have  

t=12\ years\\ P=\$10,000\\ r=10\%=10/100=0.10\\n=2  

substitute in the formula above  

A=10,000(1+\frac{0.10}{2})^{2*12}  

A=10,000(1.05)^{24}  

A=\$32,251.00  

Part c) 18 years

we have  

t=18\ years\\ P=\$10,000\\ r=10\%=10/100=0.10\\n=2  

substitute in the formula above  

A=10,000(1+\frac{0.10}{2})^{2*18}  

A=10,000(1.05)^{36}  

A=\$57,918.16

7 0
3 years ago
Plz help me 20points
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Answer:

20 according to me. I am sorry if I'm wrong

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